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Bas_tet [7]
3 years ago
15

You mix sugar in water and stir until it's completely dissolved. in this system, the water is the ________, the sugar is the ___

_____, and the end result is a ________. solute; solution; solvent solvent; solution; solute solution; solvent; solute solvent; solute; solution solute; solvent; solution
Chemistry
2 answers:
natulia [17]3 years ago
6 0
A solution is a homogenous  mixture of two or more substances. A solute is a substance that dissolves. A solvent is a substance in which other substances dissolve in. Using these definitions above the answer will hence be choice number 4. solvent;solute;solution.
mrs_skeptik [129]3 years ago
3 0

Answer: water is the solvet, sugar is the solute and the the end result is a solution.

Explanation:

Binary Solution is a homogeneous mixture of two components called as solute and solvent.

Solute is the component which is present in smaller proportion and is solid for solid in liquid solution and solvent is the component which is present in larger proportion and is liquid for solid in liquid solution.

Concentrated solution is one in which there is more amount of solid.

Dilute solution is one in which there is more amount of liquid.

Thus as sugar is lesser in amount , it is the solute. Water is preset in larger amount, thus it is the solvent and the end result is the solution.

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Be sure to answer all parts. A 0.365−mol sample of HX is dissolved in enough H2O to form 835.0 mL of solution. If the pH of the
Marta_Voda [28]

Answer:

The Ka is 9.11 *10^-8

Explanation:

<u>Step 1: </u>Data given

Moles of HX = 0.365

Volume of the solution = 835.0 mL = 0.835 L

pH of the solution = 3.70

<u>Step 2:</u> Calculate molarity of HX

Molarity HX = moles HX / volume solution

Molarity HX = 0.365 mol / 0.835 L

Molarity HX = 0.437 M

<u />

<u>Step 3:</u> ICE-chart

[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4

Initial concentration of HX = 0.437 M

Initial concentration of X- and H3O+ = 0M

Since the mole ratio is 1:1; there will react x M

The concentration at the equilibrium is:

[HX] = (0.437 - x)M

[X-] = x M

[H3O+] = 1.995*10^-4 M

Since 0+x = 1.995*10^-4   ⇒ x=1.995*10^-4

[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M

[X-] = x = 1.995*10^-4 M

<u>Step 4: </u>Calculate Ka

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Ka = ((1.995*10^-4)²)/ 0.437

Ka = 9.11 *10^-8

The Ka is 9.11 *10^-8

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