An athelete runs some distance before taking a long jump because : give answer
1 answer:
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<h2><u>We have</u>,</h2>
- Initial velocity (u) = 0 m/s
- Time taken (t) = 2.9s
- Acceleration due to gravity (g) = + 10 m/s² [Down]
- Final velocity (v)
- Height (h)
→ v = u + gt
→ v = 0 + 10(2.9)
→ v = 29 m/s … ( Ans )
And,
→ h = ut + ½gt²
→ h = 0(2.9) + ½ × 10 × (2.9)²
→ h = 5 × 8.41
→ h = 42.05 m … ( Ans )
Answer:
0.016 s
Explanation:
Initial velocity, u = 0
use the third equation of motion to find the acceleration of the rock.
Net displacement in the vertical direction would be zero. y = 0
Use second equation:
Thus, the rock will return to its initial release point in 0.016 s.