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melomori [17]
2 years ago
6

A high-speed train accelerates at a constant rate in a straight line.

Physics
1 answer:
Brilliant_brown [7]2 years ago
8 0

Answer:

1/2

Explanation:

change=

\frac{60 - 30}{60}  =  \frac{30}{60}  =  \frac{3}{6}  =  \frac{1}{2}

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How fast would you have to travel on the surface of earth at the equator to keep up with the sun (that is, so that the sun would
professor190 [17]

Answer: 1037 miles per hour

Explanation: In order to see the sun in the same position in the sky, you would have to travel against the speed of rotation of the earth, because this is what causes the sun to appear in a constantly changing position.

Because of this, we will have to calculate the speed of rotation of the earth. To get started, we must know the circumference of the earth. Assuming the circumference formula for a sphere,

Circumference=2\pi R

Where R is the radius of the earth, we find that the perimeter of the earth is approximately 24881 miles. The equation to calculate speed is given by

v=\frac{Distance}{Time}

Because the earth completes one rotation in 24 hours, we have to find the speed of rotation as the perimeter of the earth divided by 24 hours.

The obtained result is 1037 miles per hour.

You would have to travel at 1037 miles per hour in the direction opposite to the direction the rotation is ocurring in.

5 0
3 years ago
In noisy factory environments, it's possible to use a loudspeaker to cancel persistent low-frequency machine noise at the positi
Vaselesa [24]

Answer:

7.39 m or 3.61 m

Explanation:

\lambda = Wavelength

f = Frequency = 90 Hz

v = Speed of sound = 340 m/s

Path difference of the two waves is given by

s_1-s_2=\frac{\lambda}{2}

Velocity of wave

v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{340}{90}\\\Rightarrow \lambda=3.78\ m

s_1=s_2\pm\frac{\lambda}{2}\\\Rightarrow s_1=5.5\pm \frac{3.78}{2}\\\Rightarrow s_1=7.39\ m, 3.61\ m

So, the location from the worker is 7.39 m or 3.61 m

7 0
3 years ago
A proton moving at 8.9 × 106 m/s through a magnetic field of 0.96 T experiences a magnetic force of magnitude 3.8 × 10−13 N. Wha
goblinko [34]

Answer: 15.66 °

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F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.

From this expression and using the given values we obtain the following:

F/(q*v*B) = sin α

3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27

then  α =15.66°

8 0
3 years ago
What is the net force on the purple ring in the picture below. _________
Setler79 [48]
The dogs i think haha
5 0
2 years ago
A car accelerates from rest to 19 m/s in 6 seconds. What is the acceleration of the car?
choli [55]

Answer:

the car is moving so that how it gos so fast

Explanation:

7 0
3 years ago
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