Convert the following to moles 5.70 grams of ZrF4
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The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.
<h3>Oxidation and reduction</h3>Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.
In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in while that of C in CO changed from +2 to +4 in
.
Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.
More on oxidation and reduction can be found here: brainly.com/question/13699873
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Structures of <span>1-bromo-3-methyl-2-butene and </span>2-bromo-3-methyl-2-butene are shown below.
It can be seen that <span>1-bromo-3-methyl-2-butene is containing a C-H bond in which carbon is sp</span>² hybridized (i.e. =C-H) while such bonding is absent in 2-bromo-3-methyl-2-butene.
So, as we know that the peak of C-H stretching of alkenes is found in the region of 3010-3100 cm⁻¹ with medium intensity. Therefore, 1-bromo-3-methyl-2-butene will show this peak and 2-bromo-3-methyl-2-butene will lack this peak in IR spectrum.
It can be seen that <span>1-bromo-3-methyl-2-butene is containing a C-H bond in which carbon is sp</span>² hybridized (i.e. =C-H) while such bonding is absent in 2-bromo-3-methyl-2-butene.
So, as we know that the peak of C-H stretching of alkenes is found in the region of 3010-3100 cm⁻¹ with medium intensity. Therefore, 1-bromo-3-methyl-2-butene will show this peak and 2-bromo-3-methyl-2-butene will lack this peak in IR spectrum.