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Vinvika [58]
3 years ago
9

→

Chemistry
1 answer:
marin [14]3 years ago
8 0

Answer:

[A]²

Explanation:

Since the formation is independent of D, D is 0 order.

Since a quadruples when it is doubled it can be written as

2A^X= 4

To find the unknown power we can assume A= 1 to make the math simple. So When a = 2 (Because you doubled it) raised to X power it will equal 4

so the unknown power is 2

Making the rate law

[a]²[b]⁰

or simply just

[A]²

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Describe in your own words what stoichiometry is and why it is helpful to scientists? Please write at least 3 complete sentences
Nuetrik [128]
Stoichiometry measures any quantitative relationships and is used to determine the amount of products or reactants that are produced in a given reaction.
(Is that how you spell Stoichiometry)
5 0
3 years ago
Calculate the mass of 0. 4 moles of water.​
Anna [14]

Answer:

7.208 g

Explanation:

0.4mol x \frac{2(1.01) + 16.00 g}{1 mol}

= 7.208 g

You are using molar mass of H20 to find the mass. Moles of 0.4 and 1 mol cancel out leaving you with just grams. You get the values in the numerator from the periodic table and the 2(1.01) is because you have 2 of the H in H20

5 0
3 years ago
Compute the atomic density (the number of atoms per cm3 ... rather than the mass density g/cm3) for a perfect crystal of silicon
serious [3.7K]

Answer:

        \large\boxed{\large\boxed{5.00\times 10^{22}atoms/cm^3}}

Explanation:

You can convert the <em>density</em> into <em>atomic density</em> using the <em>atomic weight </em>and Avogadro's number

A dimensional analysis is very helpful:

           \dfrac{g}{cm^3}\times \dfrac{mol}{g}\times \dfrac{atoms}{mol}=\dfrac{atoms}{cm^3}

Follow the chain: g cancels with g, mol cancels with mol; at the end, what remains is atoms/cm³, which is what you want.

Use that with your data:

         \dfrac{2.33g}{cm^3}\times \dfrac{1mol}{28.09g}\times \dfrac{6.022\times 10^{23}atoms}{mol}=\approx 5.00\times10^{22}atoms/cm^3

3 0
3 years ago
Lridium-192 is an isotope of iridium and has a half-life of 73.83 days. if a laboratory experiment begins with 100 grams of irid
fiasKO [112]
Radioactive material undergoes first order dissociation kinetics.

For 1st order system,
k = 0.693 / t1/2
where, t 1/2 = half-life of the radioactive disintegration process.

Given that, t 1/2  = <span>73.83 days
Therefore, k = 0.009386 day-1

Also, for 1st order reaction,
k = </span>\frac{2.303}{t} log \frac{Co}{Ct}

Given that, Co = initial concentration of <span>Iridium-192 = 100 g

Therefore, </span>0.009386 = \frac{2.303}{t} log \frac{100}{Ct}

On rearranging we get, Ct = 100 (0.990656)^{t}

Answer: Ct = 100 (0.990656)^{t} equation approximates the amount of Iridium-192 present after t days
8 0
3 years ago
What happens in a redox reaction?
ruslelena [56]
The answer is c ! :)
3 0
3 years ago
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