Answer:
619°C
Explanation:
Given data:
Initial volume of gas = 736 mL
Initial temperature = 15.0°C
Final volume of gas = 2.28 L
Final temperature = ?
Solution:
Initial volume of gas = 736 mL (736mL× 1L/1000 mL = 0.736 L)
Initial temperature = 15.0°C (15+273 = 288 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂/V₁
T₂ = 2.28 L × 288 K / 0.736 L
T₂ = 656.6 L.K / 0.736 L
T₂ = 892.2 K
K to °C:
892.2 - 273.15 = 619°C
Answer:
This is because no energy is being created or destroyed in this system
Explanation:
I think this is correct? I hope it helps.
The volume of ethyl alcohol overflow will be 9.265mL.
To calculate the volume of ethyl alcohol overflow, we will use
∆V=V(á∆T)
Where,
∆V=volume expand
á=volumetric expansion Coefficients =0.00109/°C
V=initial volume =500ml
T'=final temp. =22°C
T=initial temp=5°C
Now,
∆V=500×(0.00109/°C) ×(22-5)
=500×(0.00109) (17)
=9.265ml
Thus, we find that the volume of ethyl alcohol overflow will be 9.265 mL.
learn more about ethyl alcohol:
brainly.com/question/11237501
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