Answer:
The flip side, of course, is that a strongly basic solution can have 100,000,000,000,000 times more hydroxide ions than a strongly acidic solution.
Explanation:
Answer : The correct option is B (clay, slit, sand).
Explanation :
Soil particles are of three types : Sand, Slit and clay. Most of the soils particles are made up of a combination of sand, slit and clay.
Particle size range of the sand = 2.00 -0.05 mm
Particle size range of the slit = 0.05 -0.002 mm
Particle size range of the sand = less than 0.002 mm
Sand is the largest soil particle, clay is the smallest soil particle and slit particle is present in between the sand & clay particle.
Therefore, the order from smaller to larger sediment particles is
Clay > Slit > Sand
Answer:
In 33.7 grams SnF2 we have 8.17 grams of F
Explanation:
Step 1: Data given
Mass of SnF2 = 33.7 grams
Molar mass of SnF2 = 156.69 g/mol
Molar mass of F = 19.00 g/mol
Step 2: Calculate moles of SnF2
Moles SnF2 = mass / molar mass
Moles SnF2 = 33.7 grams / 156.69 g/mol
Moles SnF2 = 0.215 moles
Step 3: Calculate moles F
For 1 mol SnF2 we have 2 moles F
For 0.215 moles SnF2 we have 2*0.215 = 0.430 moles F
Step 4: Calculate mass F
Mass F = moles F * molar mass F
Mass F = 0.430 moles * 19.00 g/mol
Mass F = 8.17 grams
In 33.7 grams SnF2 we have 8.17 grams of F
<h3>Answer:</h3>
18.75 grams
<h3>Explanation:</h3>
- Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
- In this case, the half-life of element X is 10 years, which means it takes 10 years for a given mass of the element to decay by half of its original mass.
- To calculate the amount that remained after decay we use;
Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives
Number of half-lives = Time for the decay ÷ Half-life
= 40 years ÷ 10 years
= 4
Therefore;
Remaining mass = 300 g × (1/2)⁴
= 300 g × 1/16
= 18.75 g
Hence, a mass of 300 g of an element X decays to 18.75 g after 40 years.
