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fredd [130]
3 years ago
15

A group of students is investigating whether copper is a better thermal conductor than aluminum. The students take a copper wire

and an aluminum wire of the same length and diameter. They put equal lengths of wax on one end of each wire and dip the other ends into a beaker of hot water. The length of wax left on the wires after 10 minutes is shown. Experimental Observations Copper Aluminum Original length of wax 2 cm 2 cm Length of wax after 10 minutes 0.7 cm 1.2 cm What was the independent variable in this experiment?
Chemistry
2 answers:
Verizon [17]3 years ago
6 0
The independent variables are the copper and aluminum wires.
Salsk061 [2.6K]3 years ago
5 0

Answer:

In the mentioned experiment, three kinds of variables are used, that is, the independent variable, the dependent variable, and the controlled variable. Of these the independent variables are the one that does not get modify, however, can be modified by the scientist, while the dependent variables are the one that modifies when the independent variables modify, and the controlled variables are the ones that are maintained same throughout.  

In the given experiment, the length of the wire, the type of the wire utilized, and the thermal conductivity of the wire are the independent variables.  

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2 years ago
Which of the following is part of photosynthesis, but not part of cellular respiration?
Licemer1 [7]

Answer:

A

Explanation:

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8 0
2 years ago
What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
AlladinOne [14]

The question is incomplete, here is the complete question:

The given chemical reaction is:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

<u>Answer:</u> The theoretical yield of copper is 44.48 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of aluminium = 12.6 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol

The given chemical equation follows:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of copper

So, 0.467 moles of aluminium will produce = \frac{3}{2}\times 0.467=0.7005mol of copper

Now, calculating the mass of copper  from equation 1, we get:

Molar mass of copper = 63.5 g/mol

Moles of copper = 0.7005 moles

Putting values in equation 1, we get:

0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g

Hence, the theoretical yield of copper is 44.48 grams

4 0
3 years ago
Which statement is not true about constitutional isomers?
Katyanochek1 [597]

Answer: They always have the same functional groups.

Explanation:

use quizlet too if you have toooo

3 0
2 years ago
Read 2 more answers
3. Mr. Hill has 27 students in his class
stich3 [128]
Just dived both numbers by two
4 0
3 years ago
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