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fredd [130]
3 years ago
15

A group of students is investigating whether copper is a better thermal conductor than aluminum. The students take a copper wire

and an aluminum wire of the same length and diameter. They put equal lengths of wax on one end of each wire and dip the other ends into a beaker of hot water. The length of wax left on the wires after 10 minutes is shown. Experimental Observations Copper Aluminum Original length of wax 2 cm 2 cm Length of wax after 10 minutes 0.7 cm 1.2 cm What was the independent variable in this experiment?
Chemistry
2 answers:
Verizon [17]3 years ago
6 0
The independent variables are the copper and aluminum wires.
Salsk061 [2.6K]3 years ago
5 0

Answer:

In the mentioned experiment, three kinds of variables are used, that is, the independent variable, the dependent variable, and the controlled variable. Of these the independent variables are the one that does not get modify, however, can be modified by the scientist, while the dependent variables are the one that modifies when the independent variables modify, and the controlled variables are the ones that are maintained same throughout.  

In the given experiment, the length of the wire, the type of the wire utilized, and the thermal conductivity of the wire are the independent variables.  

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A spider has several eyes.
NikAS [45]
The main function is to help them see with all their eyes.
4 0
2 years ago
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Un globo lleno de helio tenia un volumen de 8.5 L en el suelo a 20°C y a una presión de 750 torr. Cuando se le soltó, el globo s
Ray Of Light [21]

Answer:

El volumen del gas era 12.95 L

Explanation:

Se relaciona la presión y el volumen mediante la ley de Boyle, que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:  P*V=k

Por otro lado, la Ley de Charles consiste en la relación que existe entre el volumen y la temperatura absoluta de una cierta cantidad de gas ideal, el cual se mantiene a una presión constante. Esta ley dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T}=k

Por último, la Ley de Gay Lussac dice que la temperatura absoluta y la presión son directamente proporcionales. Es decir, cuando se mantiene todo lo demás constante, mientras suba la temperatura de un gas subirá también su presión. Y mientras la temperatura del gas baje, lo mismo ocurrirá con la presión:

\frac{P}{T}=k

Combinado las mencionadas tres leyes se obtiene:

\frac{P*V}{T} =k

Cuando se desean estudiar dos diferentes estados, uno inicial y una final de un gas, se puede aplicar:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Recordando que la temperatura debe usarse en grados Kelvin, conoces los siguientes datos:

  • P1: 750 torr
  • V1: 8.5 L
  • T1: 20°C= 293°K (siendo 0°C=273°K)
  • P2: 425 torr
  • V2: ?
  • T2: -20°C= 253 °K

Reemplazando:

\frac{750 torr*8.5 L}{293K} =\frac{425 torr*V2}{253 K}

Resolviendo:

V2=\frac{750 torr*8.5 L}{293K} *\frac{253 K}{425 torr}

V2= 12.95 L

<u><em>El volumen del gas era 12.95 L</em></u>

<u><em></em></u>

5 0
2 years ago
The potential in an electrochemical cell, E, is related to the Gibb's free energy change (ΔG) for the overall cell redox reactio
Nana76 [90]

Answer:

Explanation:

As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)

ΔG = ΔG° + RTInQ

Q = 1

ΔG = ΔG°

ΔG = =nFE°

n=no of electrons transfered.

E° = 1.1v

ΔG° = -2 * 96500 * 1.10

= -212300J

ΔG° =-212.3kJ/mol

<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>
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3 years ago
If you have 12 atoms of hydrogen before a chemical reaction, how many atoms of hydrogen will be present
soldi70 [24.7K]

Answer:

《HOPE IT WILL HELP YOU 》

Explanation:

I think the present atom of hydrogen will 1

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3 years ago
Convert the following to grams, <br> a. 0.100 moles of CO2
Svetlanka [38]
.100 mol CO2 x \frac{44.01 g}{1 mol}
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I hate to do this, but
https://youtu.be/Pft2CASl0M0 is a link to a mr andersen video. I dislike watching these cause this is what my teacher uses instead of actually having to teach herself.
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2 years ago
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