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Makovka662 [10]
4 years ago
11

8. There are different characteristics for each of the states of matter. Which statement

Physics
1 answer:
Ahat [919]4 years ago
5 0

Answer:

a. Temperatures increase can change a solid to a liquid, but cannot change a liquid to a solid

b. The particles in a solid are much closer together than the particles in a liquid.

Explanation:

Any material expands when heated and contracts when cooled. So, when a body is heated to a particular temperature, it starts melting and changes into a liquid.

As the material expands the distance between the atoms or molecules increases and it will become a liquid. So it can move around the material. It doesn't become solid on further heating. But water is an exception where it contracts when heated from 0° to 4° C.

In solids, these atoms or molecules are closely packed. It is rigidly fixed.

The solid, as well as the liquid, has a definite volume, but the liquid does not have a definite shape.

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Karo-lina-s [1.5K]

Answer: its b because  as soon as you go far away from light it get red and dents

Explanation:

8 0
3 years ago
Give an example of a collision in real life. Use the law of conservation of energy to describe the transfer of momentum. Be sure
ozzi

Explanation :

Using the law of conservation of energy  

When two cars collide with each other then the momentum is same before collision and after collision but energy is changed after collision in form of heat and sound.

We know this collision is inelastic collision.

In Inelastic collision, when two objects collide with each other then the momentum is conserved but kinetic energy is not conserved.  

7 0
4 years ago
Solve 3x+1<br><img src="https://tex.z-dn.net/?f=%20%5Cleqslant%201" id="TexFormula1" title=" \leqslant 1" alt=" \leqslant 1" ali
Rzqust [24]

3x + 1 ≤ 1

Subtract 1 from each side:  3x ≤ 0

Divide each side by  3 :     <em>x ≤ 0</em>

8 0
3 years ago
An object is dropped from a height of 75.0 m above ground level. (a) determine the distance traveled during the first second.
barxatty [35]

The relevant formula we can use in this case would be:

h = v0 t + 0.5 g t^2

where,

h = height or distance travelled

v0 = initial velocity = 0 since it was dropped

t = time = 1 seconds

g = 9.8 m/s^2

 

So calculating for height h:

h = 0 + 0.5 * 9.8 m/s^2 * (1 s)^2

<span>h = 4.9 meters</span>

6 0
3 years ago
A bicycle wheel with radius 0.3 m rotates from rest to 3 rev/s in 5 s. What is the magnitude and direction of the total accelera
AlekseyPX

Answer:

Explanation:

Given

Radius of bicycle wheel r=0.3\ m

Initial angular velocity \omega _0=0

It rotates 3 revolution in 5 s therefore

\omega =2\pi 3=\6\pi =18.85\ rad/s

using \omega =\omega _0+\alpha t

where \alpha =angular\ acceleration

\omega =Final\ angular\ velocity

t=time

\alpha =\frac{18.85}{5}=3.77 rad/s^2

Total acceleration of any point will be a vector sum of tangential acceleration and centripetal acceleration

\omega at t=1

\omega =0+3.77\times 1=3.77 rad/s

a_c=\omega ^2\cdot r

a_c=(3.77)^2\cdot 0.3=4.26 m/s^2

Tangential acceleration a_t=\alpha \times r

a_t=3.77\times 0.3=1.13 m/s^2

a_{net}=\sqrt{a_t^2+a_c^2}

a_{net}=\sqrt{(1.13)^2+(4.26)^2}

a_{net}=4.41 m/s^2

                       

7 0
4 years ago
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