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krok68 [10]
3 years ago
7

what does the term equilibrium refer to? a. the resting position of the wave b. the highest point in the wave c. the lowest poin

t of the wave d. the next subsequent wave e. the period of the wave
Physics
2 answers:
Brums [2.3K]3 years ago
7 0
A. the resting position of a wave
djverab [1.8K]3 years ago
6 0

Answer:

a. the resting position of the wave

Explanation:

The equilibrium refers to the resting position of the wave or the position it would be if it was undisturbed. And this is normally exactly midway between the highest point of the wave and the lowest point of the wave.

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A wave has 25 wavelengths in 5 secs. The frequency of the wave is _.
kati45 [8]
Heyyyy I wish I could help but I don’t know
7 0
3 years ago
Calculate the wavelength of the electromagentic waves with the given frequencies, and determine the type of electromagnetic radi
ololo11 [35]

To develop this problem we require the concepts related to wavelength and its expression to calculate it.

The wavelength is given by

\lambda =\frac{c}{f}

Where,

c=3*10^8 m/s light velocity

f = frequency.

Our values are given by,

f_1=4.38*10^{14}Hz

f_2= 4.14*10^{20}Hz

f_3 = 3.24*10^{12}Hz

Then,

\lambda_1=\frac{3*10^8}{4.38*10^{14}}= 6.8493*10^{-7}m Visible

\lambda_2=\frac{3*10^8}{4.14*10^{20}}= 7.24*10^{-13}m Gamma Ray

\lambda_3=\frac{3*10^8}{3.24*10^{12}}= 9.259*10^{-5}m Infrared

<em>*Note the designation on the type of rays that are, can be found in consulted via On-line or in the optical books referring to the electromagnetic spectrum table with their respective ranges.</em>

5 0
3 years ago
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
Katen [24]

Answer:

9.4 m/s

Explanation:

The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.

So we can write:

W=K_f - K_i

where in this problem:

W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving for Kf,

K_f = W+K_i = -36,733+66,120=29,387 J

The kinetic energy of the car can be also written as

K_f = \frac{1}{2}mv^2

where:

m = 661 kg is the mass of the car

v is its final speed

Solving, we find

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

8 0
3 years ago
What is the distance from the earth's center to a point outside the earth where the gravitational acceleration due to the earth
Crazy boy [7]
R2^ 2 / R1 ^2 = g1 / g2 = 38 

<span>R2 = R1 x √38 = 6.1644* R1 </span>

<span>R2 = 6.1644 x 6378 000 = 39316632.5 m</span>
8 0
3 years ago
A car is driving at 50 kilometers per hour. how far, in meters, does it travel in 2 seconds?
AveGali [126]
<span>Sure, Just change the 2 sec. into hrs. Since 1 hour = 3600 sec. then you can divide 2/3600 = 1/1800 hrs. Distance in kilometers = (Speed in km/hr * time in hrs) = 50*(1/1800)*1000 in meters = 27.77 meters</span>
7 0
3 years ago
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