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4 years ago

What is the difference between a general and a specific tolerance, and how can you tell the difference on a drawing?

1 answer:

6 0

<span>During the reading of a blueprint, a general tolerance pertains to all dimensions that are not independently identified. All tolerances are +\- .030. General tolerances are mostly found in the blueprint’s set of information. Let’s say for example, a compact tolerance is required, then a specific tolerance is considered for specific areas of the blueprint. These kinds of tolerances are commonly found along the affected area.</span>

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An AC voltage source has an output of ∆V = 160.0 sin(495t) Volts. Calculate the RMS voltage. Tries 0/20 What is the frequency of

kupik [55]

Answer:

RMS voltage is 113.1370 V

frequency is 780.685 Hz

voltage is −158.66942 V

maximum current is 2.9739 A

Explanation:

Given data

∆V = 160.0 sin(495t) Volts

so Vmax = 160

and angular frequency = 495

time t = 1/106 s

resistor R = 53.8 Ω

to find out

RMS voltage and frequency of the source and voltage and maximum current

solution

we know voltage equation = Vmax sin ωt

here Vmax is 160 as given equation in question

so RMS will be Vmax / √2

RMS voltage = 160/ √2

RMS voltage is 113.1370 V

and frequency = angular frequency / 2π

so frequency = 497 / 2π

frequency is 780.685 Hz

voltage at time (1/106) s

V(t) = 160.0 sin(495/ 108)

voltage = −158.66942 V

so current from ohm law at resistor R 53.8 Ω

maximum current = voltage max / resistor

maximum current = 160 / 53.8

maximum current = 2.9739 A

8 0

3 years ago

Consider a fuel cell operating at 800∘C, 1 atm. In the cathode, humidified air is supplied with the mole fraction of water vapor

lara [203]

Answer:

The maximum velocity that can be used while still maintaining laminar flow is

$V_{max} = \ 272 m/s$

Explanation:

The explanation is shown on the first and second uploaded image

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4 years ago

A 3.00-kg object has a velocity 16.00 i ^ 2 2.00 j ^2 m/s.

trapecia [35]

Answer:

390 J

Explanation:

m = 3 kg

u = 16 i + 2 j

(a) Magnitude of velocity = $\sqrt{16^{2}+2^{2}}$ = 16.1245 m/s

KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J

(b) v = 18 i + 14 j

Magnitude of velocity = $\sqrt{18^{2}+14^{2}}$ = 22.804 m/s

KEf = 1/2 m v^2 = 0.5 x 3 x 22.804 = 780 J

According to the work energy theorem

Work done = change in KE = KEf - KEi = 780 - 390 = 390 J

8 0

4 years ago

Paul made a diagram to compare and contrast radio waves that are used for communication and for broadcasting. Which labels belon

Vesna [10]

Answer: (A) "X: May use LF, HF, and UHF waves

Y: Travels at the speed of light

Z: May use MF and VHF waves"

6 0

4 years ago

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Pretend you are explain net force to someone much younger than you. Explain how to calculate net force and how the net force det

jeka57 [31]

Answer:

you can tell them it is the amount of "push" on an object then you can explain using a soccer ball being kicked or a cart being pushed

Explanation:

4 0

3 years ago