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3 years ago

A grapefruit has a weight on earth of 4.9 newtons. What is the grapefruit's mass?

2 answers:

3 0

Weight = mg where m = mass and g = gravity = 10 (9.81....)
so m = w/g = 4.9 / 10(9.81....) = 0.49 (0.49949....)
if you get given g as 10, answer is 0.49 kg
if you get given g as 9.81, answer is 0.50 (1sf)

igor_vitrenko [27]3 years ago

3 0

Answer:

The grapefruit's mass is 0.5 kg.

Explanation:

Given that,

Weight = 4.9 N

We need to calculate the mass

Using formula of newton's second law

$F = mg$

$m = \dfrac{F}{g}$

Where, F = weight on earth

g = acceleration due to gravity

Put the value into the formula

$m = \dfrac{4.9}{9.8}$

$m =0.5\ kg$

Hence, The grapefruit's mass is 0.5 kg.

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The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it i

andreyandreev [35.5K]

The apparent weight of a 1.1 g drop of water is 4.24084 N.

<h3>What is Apparent Weight?</h3>

According to physics, an object's perceived weight is a characteristic that describes how heavy it is. When the force of gravity acting on an object is not counterbalanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.
By definition, an object's weight is equal to the strength of the gravitational force pulling on it. It follows that even a "weightless" astronaut in low Earth orbit, with an apparent weight of zero, has almost the same weight that he would have if he were standing on the ground; this is because the gravitational pull of low Earth orbit and the ground are nearly equal.

Solution:

N = Speed of rotation = 1250 rpm

D = Diameter = 45 cm

r = Radius = 22.5 cm

M = Mass of drop = 1.1 g

Angular speed of the water = $\omega = \frac{2\pi N}{60}$

$\omega = \frac{2\pi \times 1250}{60}$

$\omega = 130.89 rad/s$

Apparent weight is given by

$W _a = M\omega^{2}R$

$W_a = 1.1 \times 10^-^3\times (130.89)^2\times 0.225$

$W_a$ = 4.24084 N

Know more about Apparent weight brainly.com/question/14323035

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Question:

The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 45-cm-diameter drum spins at 1250 rpm around a vertical axis. What is the apparent weight of a 1.1 g drop of water?

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2 years ago

Water flows over a section of Niagara Falls at the rate of 1.4 × 106 kg/s and falls 49.8 m. How much power is generated by the f

Ad libitum [116K]

Answer:

Power= 6.84×10⁸ W

Explanation:

Given Data

Niagara falls at rate of=1.4×10⁶ kg/s

falls=49.8 m

To find

Power Generated

Solution

Regarding this problem

GPE (gravitational potential energy) declines each second is given from that you will find much the kinetic energy of the falling water is increasing each second.

So power can be found by follow

Power= dE/dt = d/dt (mgh)

Power= gh dm/dt

Power= 1.4×10⁶ kg/s × 9.81 m/s² × 49.8 m

Power= 6.84×10⁸ W

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3 years ago

Help on the question (blue letters)

Nataliya [291]

Answer:

The top of the mountian is colder

Explanation:

As air rises, the pressure decreases. It is this lower pressure at higher altitudes that causes the temperature to be colder on top of a mountain than at sea level.

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3 years ago

A ball is thrown horizontally at a speed of 24 meters per second from the top of a cliff. if the ball hits the ground 4.0 second

Viktor [21]

Answer:

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Explanation:

To obtain the height of the cliff;

We can use the Relation to obtain the final velocity, v

v = u + at

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v = 0 + (9.8*4)

v = 0 + 39.2

v = 39.2 m/s

To obtain the Height, S

v² = u² + 2aS

39.2^2 = 0 + 2(9.8)S

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1536.64 = 19.6S

S = 1536.64 / 19.6

S = 78.4 m

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3 years ago