a professional baseball player can pitch a baseball with a velocity of 44.7m/s towards home plate. If a baseball weighs 1.4 N, h
2 answers:
Answer:
p = 6.25 kg-m/s
Explanation:
It is given that,
Velocity of the baseball, v = 44.7 m/s
Weight of the baseball, W = 1.4 N
Firstly we need to find the mass of the baseball. It can be calculated as :
m = 0.14 kg
The momentum of an object is equal to the product of mass and velocity. It is given by :
p = 6.25 kg-m/s
So, the momentum it have when it hits the catcher is 6.25 kg-m/s. Hence, this is the required solution.
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For the part a) we need only the momentum of the box and we have the data to find it.
Momentum is given by,
where clearly, p is the momentum, m the mass of the box and v is the velocity.
Substituting,
For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,
<em>It is the same that part a)</em>
Answer:
The magnitude of each charge is
Explanation:
Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.
We need to calculate the magnitude of each charge
Using formula of force
Where, q = charge
r = separation
Put the value into the formula
Hence, The magnitude of each charge is