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anastassius [24]
3 years ago
9

For the following question neglect air resistance. Pay particular attention to whether the answer involves "absolute" quantities

that have only magnitude (e.g., speed) or quantities that can have either sign (e.g., velocity). Take upward to be the positive direction.If the ball that is thrown downward has an acceleration of magnitude a a at the instant of its release (i.e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between a a and g g, the magnitude of the acceleration of gravity?If the ball that is thrown downward has an acceleration of magnitude \texttip{a}{a}a at the instant of its release (i.e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between \texttip{a}{a}a and \texttip{g}{g}g, the magnitude of the acceleration of gravity?
Physics
1 answer:
tankabanditka [31]3 years ago
8 0

Answer:a=g

Explanation: when the ball is thrown downwards gravity is acting on the ball, there is no force opposing gravity therefore it's acceleration will be due to gravity acting on it that is why a=g

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A water bath in a physical chemistry lab is 1.55 m long, 0.710 m wide, and 0.570 m deep (high). If it is filled to within 3.55 i
Lesechka [4]

Answer:

528 liter.

Explanation:

Volume of the tank(cuboid) = l*b*h

But volume of the water = l*b*h

Where

l= length of the tank

b = width of the tank

h = the length from the bottom of the tank,

3.55 in to m,

0.09017m

Length of the water in the tank = 0.570 - 0.09017

= 0.47983 m.

Volume = 0.47983*0.710*1.55

= 0.528 m3.

1 m3 = 1000 liter.

0.528 m3 = 0.528*1000

= 528 liter

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