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anastassius [24]
4 years ago
9

For the following question neglect air resistance. Pay particular attention to whether the answer involves "absolute" quantities

that have only magnitude (e.g., speed) or quantities that can have either sign (e.g., velocity). Take upward to be the positive direction.If the ball that is thrown downward has an acceleration of magnitude a a at the instant of its release (i.e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between a a and g g, the magnitude of the acceleration of gravity?If the ball that is thrown downward has an acceleration of magnitude \texttip{a}{a}a at the instant of its release (i.e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between \texttip{a}{a}a and \texttip{g}{g}g, the magnitude of the acceleration of gravity?
Physics
1 answer:
tankabanditka [31]4 years ago
8 0

Answer:a=g

Explanation: when the ball is thrown downwards gravity is acting on the ball, there is no force opposing gravity therefore it's acceleration will be due to gravity acting on it that is why a=g

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The average force ≅ 519.44 N.

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Impulse = change in momentum of a body

i.e Ft = m(v - u)

where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.

m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s

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