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Katyanochek1 [597]
3 years ago
10

One kilogram-meter per second squared is also equal to what unit

Physics
1 answer:
yan [13]3 years ago
8 0
Metres/second² is acceleration. maybe a bit more clarification?

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a 1600 kg car on flat ground is moving 6.25 m/s. its engine creates 1150 N forward force as the car moves 45.8 m. what is it fin
Sveta_85 [38]

Answer:

83,900 J

Explanation:

First, find the acceleration:

F = ma

1150 N = (1600 kg) a

a = 0.719 m/s²

Now find the final velocity.

Given:

Δx = 45.8 m

v₀ = 6.25 m/s

a = 0.719 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (6.25 m/s)² + 2 (0.719 m/s²) (45.8 m)

v = 10.2 m/s

Now find the final KE:

KE = ½ mv²

KE = ½ (1600 kg) (10.2 m/s)²

KE = 83,920 J

Rounded to three significant figures, the final kinetic energy is 83,900 J.

6 0
4 years ago
Helo am desperate answer quick will give brainliest
Anika [276]

Answer:

Pitch. The sound an article makes changes relying upon how quick it is vibrating. At the point when an item vibrates rapidly, sharp sounds are heard. Low-pitched sounds come from things that vibrate all the more gradually.

Explanation:

7 0
3 years ago
Read 2 more answers
25 points! Will Mark Brainliest! Answer Asap!
Lubov Fominskaja [6]
<span>This can be explained by the effect of a material-specific parameter called Thermal conductivity. How well a material conducts heat is called Thermal conductivity. Metal has a greater thermal conductivity co-efficient and hence conducts heat very well Cardboard, on the other hand, is a very poor heat conductor. C</span>ardboard is composed of cellulose, a polymer that has no free electrons. Without <span>free electrons materials can neither conduct electricity or heat efficiently.</span>
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3 years ago
If your car was traveling at 60 mph, that is about 27m/s. How long would it take a car traveling at 27m/s to slow to a stop, if
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Answer:

vf=at+v0. vf=0

-v0=at

t=-v0/a=(-27m/s)/(-8m/s^2)=3.4s

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3 years ago
The acceleration of a particle moving only on a horizontal xy plane is given by , where is in meters per second-squared and t is
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<span>Integrate a to get v and use initial data for v to evaluate the constants of integration. v = [(3/2)t^2 + Ci]i + [2t^2 + Cj]j When t=0, v = 5i + 2j, hence Ci=5, Cj=2 So v = [(3/2)t^2 + 5]i + [2t^2 + 2]j <==ANS (b) Integrate v to get r and use initial data for r to evaluate the constants of integration: The result is: r = [0.5t^3 + 5t + 20]i + [(2/3)t^3 + 2t + 40]j <==ANS Set t=4 in the above expression to evaluate (c) Convert the result of (c) to polar form to evaluate (d)</span>
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