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geniusboy [140]
3 years ago
9

Not much of a question :/ dont answer

Engineering
1 answer:
Mamont248 [21]3 years ago
5 0

Answer: ok

Explanation: this is totally not an answer

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Concrete ___ support and anchor the bottom of steel columns and wood post, which support beams that are pare of framing system o
dolphi86 [110]
I wanna say it’s D post support
3 0
3 years ago
The southernmost rim inlet elevation on the topographical survey is
Lynna [10]

The southernmost rim inlet elevation on the topographical survey is approximately 4.5 feet below the benchmark on the north side of West 55th Street.

What is topographical survey?

A topographical survey, often known as a land survey or topographical land survey, is a type of survey that includes contours. Topographical land surveying determines the exact location and specifications of natural and man-made features on a piece of land. The survey is then turned into a suitable and thorough plan, which incorporates man-made characteristics such as boundaries, neighbouring buildings, sidewalks, and so on. Natural elements such as trees, ponds, and ground contours are also detected by the topographical survey. Having a clear and accurate map of your property might help you avoid costly downstream mistakes caused by unforeseen challenges. It can supply you with the information you need about the land before making any alterations to it.

To learn more about topographical survey

brainly.com/question/14529986

#SPJ13

6 0
1 year ago
A bridge to be fabricated of steel girders is designed to be 500 m long and 12 m wide at ambient temperature (assumed 20°C). Exp
Volgvan

Answer:

a) 22.5number

b) 22.22 m length

Explanation:

Given data:

Bridge length = 500 m

width of bridge = 12 m

Maximum temperature = 40 degree C

minimum temperature  = - 35 degree C

Maximum expansion can be determined as

\Delta L = L \alpha (T_{max} - T_{min})

where , \alpha is expansion coefficient = 12\times 10^{-6} degree C

SO, \Delta L = 500\times 12\times 10^{-6}\times ( 40 - (-35))

\Delta L = 0.45 m = 450 mm

number of minimum expansion joints is calculated as

n = \frac{450}{20} = 22.5

b) length of each bridge

Length = \frac{500}{22.5} = 22.22 m

8 0
3 years ago
The pressure gage on a 2.5-m^3 oxygen tank reads 500 kPa. Determine the amount of oxygen in the tank if the temperature is 28°C
s2008m [1.1K]

Answer:

19063.6051 g

Explanation:

Pressure = Atmospheric pressure + Gauge Pressure

Atmospheric pressure = 97 kPa

Gauge pressure = 500 kPa

Total pressure = 500 + 97 kPa = 597 kPa

Also, P (kPa) = 1/101.325  P(atm)

Pressure = 5.89193 atm

Volume = 2.5 m³ = 2500 L ( As m³ = 1000 L)

Temperature = 28 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.2 + 273.15) K = 301.15 K  

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

5.89193 atm × 2500 L = n × 0.0821 L.atm/K.mol × 301.15 K  

⇒n = 595.76 moles

Molar mass of oxygen gas = 31.9988 g/mol

Mass = Moles * Molar mass = 595.76 * 31.9988 g = 19063.6051 g

7 0
3 years ago
2.4: Add a method called setValue(), and the description of setValue is: public int setValue(long searchKey) In this method, the
Yanka [14]

Answer:

Below is java code that must be used for the given question:

// highArray.java

// demonstrates array class with high-level interface

// to run this program: C>java HighArrayApp

////////////////////////////////////////////////////////////////

class HighArray

  {

  private long[] a;                 // ref to array a

  private int nElems;               // number of data items

  //-----------------------------------------------------------

  public HighArray(int max)         // constructor

     {

     a = new long[max];                 // create the array

     nElems = 0;                        // no items yet

     }

  //-----------------------------------------------------------

  public setValue find(long searchKey)

     {                              // find specified value

     int j;

     for(j=0; j<nElems; j++)            // for each element,

        if(a[j] == searchKey)           // found item?

           break;                       // exit loop before end

     if(j == nElems)                    // gone to end?

        return false;                   // yes, can't find it

     else

        return true;                    // no, found it

     }  // end find()

  //-----------------------------------------------------------

  public void insert(long value)    // put element into array

     {

     a[nElems] = value;             // insert it

     nElems++;                      // increment size

     }

  //-----------------------------------------------------------

  public void display()             // displays array contents

     {

     for(int j=0; j<nElems; j++)       // for each element,

        System.out.print(a[j] + " ");  // display it

     System.out.println("");

     }

  //-----------------------------------------------------------

  }  // end class HighArray

////////////////////////////////////////////////////////////////

class HighArrayApp

  {

  public static void main(String[] args)

     {

     int maxSize = 100;            // array size

     HighArray arr;                // reference to array

     arr = new HighArray(maxSize); // create the array

     arr.insert(77);               // insert 10 items

     arr.insert(99);

     arr.insert(44);

     arr.insert(55);

     arr.insert(22);

     arr.insert(88);

     arr.insert(11);

     arr.insert(00);

     arr.insert(66);

     arr.insert(33);

     arr.display();                // display items

     int searchKey = 35;           // search for item

     if( arr.find(searchKey) )

        System.out.println("Found " + searchKey);

     else

        System.out.println("Can't find " + searchKey);

     }  // end main()

  }  // end class HighArrayApp

Explanation:

6 0
3 years ago
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