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geniusboy [140]
3 years ago
9

Not much of a question :/ dont answer

Engineering
1 answer:
Mamont248 [21]3 years ago
5 0

Answer: ok

Explanation: this is totally not an answer

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What type of engineering do you think would help solve this SDG???
OleMash [197]

Answer:

Explanation:

Planning engineering

4 0
3 years ago
R-134a vapor enters into a turbine at 250 psia and 175°F. The temperature of R-134a is reduced to 20°F in this turbine while its
attashe74 [19]

Answer:

Δ enthalpy = -23 Btu/Ibm

Explanation:

Given data:

Pressure ( P1 ) = 250 psi

Initial Temperature ( T1 ) = 175°F

Final temperature ( T2 ) = 20°F

<u>Calculate the change in the enthalpy of R-134a </u>

From R-134 table

h1 = 129.85 Btu/Ibm

s1 = 0.23281 Btu/Ibm.R

note : entropy is constant  

hence ; s1 = s2

by interpolation  ; h2 = 106.95

Δ enthalpy = h2 - h1

                  =  ( 106.95 - 129.85 ) = -23 Btu/Ibm

5 0
2 years ago
hree large plates are separated bythin layers of ethylene glycol and water. The top plate moves to the right at 2m/s. At what sp
MakcuM [25]

Answer: For the center plate to remain stationed in one position without rotating, the bottom plate has to move to the left at a speed of 2m/s, so as to cancel the force acting on it from the top.

The center plate will not move when the bottom plate is moving left in a speed of 2m/s to counter the speed of the top plate, because a body will continue to be at rest if all the forces acting towards the body are equal. The center plate will be at rest because we have directed equal force from the top and bottom of the plate.

3 0
3 years ago
Silicone elastomers, for use in seals and gaskets, are not compatible with which refrigerants?
s2008m [1.1K]

Answer

Silicone elastomers, for use in seals and gaskets, are not compatible with which refrigerants? answer is HFO'S

Explanation:

3 0
2 years ago
A 15,000 kg satellite is orbiting at 800 km above the Earth’s surface. What is the potential energy of the satellite?
vredina [299]

Answer:

-8.34\times 10^{11}\ \text{J}

Explanation:

m = Mass of satellite = 15000 kg

h = Distance above Earth = 800 km

R = Radius of Earth = 6371 km

M = Mass of Earth = 5.972\times 10^{24}\ \text{kg}

G = Gravitational constant = 6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2

Potential energy is given by

U=-\dfrac{GMm}{R+h}\\\Rightarrow U=-\dfrac{6.674\times 10^{-11}\times 5.972\times 10^{24}\times 15000}{(6371+800)\times 10^3}\\\Rightarrow U=-8.34\times 10^{11}\ \text{J}

The potential energy of the satellite is -8.34\times 10^{11}\ \text{J}.

6 0
3 years ago
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