Not much of a question :/ dont answer

Hydrogen enters the turbine of an Ericsson cycle at 1040 K, 5 bar with a mass flow rate of 1 kg/s. At the inlet to the compresso

andrew11 [14]

Answer:

a)

Calculate the net power developed by using

the following relation:

Wste=W-W.

Substitute 8728 kw for w, and 2846 kw for w..

Wyle=8728 - 2846

= 5882 kW

Therefore, the net power developed is 5882 kW).

Comment

Step 6 of 7 A

Calculate the thermal efficiency by using the

following relation:

Here, e, is the heat input.

Substitute w, for ..

w

Substitute s882 kw for ws and 8728 kw for w.

5882

1-8728

67.39%

Therefore, the thermal efficiency is 67.39%).

Comments (3)

Step 7 of 7 A

Calculate the back work ratio.

bwr =

Substitute 8728 kw for w, and 2846 kw for w..

bwr - 2846

bwr=8728

=0.326

Therefore, the back work ratio is 10.326).

Explanation:

7 0

3 years ago

The constant A in Equation 17.2 is 12π4 R/5(θD) 3 where R is the gas constant and θD is the Debye temperature (K). Estimate θD f

kirill115 [55]

Answer:

The Debye temperature for aluminum is 375.2361 K

Explanation:

Molecular weight of aluminum=26.98 g/mol

T=15 K

The mathematical equation for the specific heat and the absolute temperature is:

$C_{v} =AT^{3}$

Substituting in the expression of the question:

$C_{v} =(\frac{12\pi ^{4}R }{5\theta _{D}^{3} } )T^{3}$

$\theta _{D} =(\frac{12\pi ^{4}RT^{3} }{5C_{v} } ) ^{1/3}$

Here

$C_{v} =4.6\frac{J}{kg-K} *\frac{1kg}{1000g} *\frac{26.98g}{1mol} =0.1241J/mol-K$

Replacing:

$\theta _{D} =(\frac{12\pi ^{4}*8.31*15^{3} }{5*0.1241} )^{1/3} =375.2361K$

3 0

3 years ago

Why is an integrated circuit (IC) referred to as a special device?"<br> points more than 10 plz help

sladkih [1.3K]

Answer:

Because IC microcomputers are smaller and more versatile than previous control mechanisms, they allow the equipment to respond to a wider range of input and produce a wider range of output. They can also be reprogrammed without having to redesign the control circuitry

Explanation:

5 0

3 years ago

According to the

zysi [14]

Answer:

The part of the system that is considered the resistance force is;

B

Explanation:

The simple machine is a system of pulley that has two pulleys

The effort, which is the input force at A gives the value of the tension at C and D which are used to lift the load B

Therefore, we have;

A = C = D

B = C + D = C + C = 2·C

∴ C = B/2

We have;

C = B/2 = A

Therefore, with the pulley only a force, A equivalent to half the weight, B, of the load is required to lift the load, B

The resistance force is the constant force in the system that that requires an input force to overcome in order for work to be done

It is the force acting to oppose the sum of the other forces system, such as a force acting in opposition to an input force

Therefore, the resistance force is the load force, B, for which the input force, A, is required in order for the load to be lifted.

3 0

3 years ago

1. A soil core sampling tube of 4 cm diameter, 12 cm length and initial mass of 0.525 kg (sample only), was dried at 105o C and

belka [17]

Answer:

porosity = 0.07 or 7%

dry bulk density = 3.25g/cm3]

water content =

Explanation:

bulk density = dry Mass / volume of sample

dry mass = 0.490kg = 490g

volume = πr2h = 3.142 * 2 *2 *12 = 150.8cm3

density = 490/150.8 = 3.25g/cm3

porosity = $\frac{wet mass - dry mass }{wet mass}$ = $\frac{0.525 - 0.49}{0.525}$ = 0.07 or 7%

water content = $\frac{wet mass - dry mass}{wet mass}$ = 7%

8 0

4 years ago

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