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NARA [144]
3 years ago
7

What type of energy is present in a barbell being lifted or a shot-put being thrown?

Physics
1 answer:
Ray Of Light [21]3 years ago
6 0
I wound say its D eltrical energy I wouldn't say B thermal energy It rather A or C.



I would say C chemical energy but its not changing so let's go with thermal energy.


Your answer will be B thermal energy.
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Help I’ll cash app you $5 if you get it right!
Thepotemich [5.8K]

Answer: B and E

Explanation:

8 0
3 years ago
Read 2 more answers
How does increased pressure result in the formation of a mineral?
drek231 [11]
The best answer is 
A) <span>The atoms in the mineral get rearranged

Over time, and under great pressure, the atoms of a substance can become rearranged, forming a new substance. For example, the intense pressure that carbon underground experiences, perhaps in the form of coal, can rearrange the atoms of the substance to create a diamond. </span>
5 0
4 years ago
Arigid body must rotate about an axis in order for it to have angular momentum about that axis. True False
kompoz [17]

Answer:

False

Explanation:

Let's consider the definition of the angular momentum,

\vec{L} = I \vec{\omega}

where I = \int\limits_m r^2 dm = \lim_{n \to \infty} \sum\limits_{i=1}^n m_i r_i^2 is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,

\vec{\omega} = \frac{\vec{r} \times \vec{v}}{r^2} so \vec{\omega} \neq 0 unless \vec{r} ║  \vec{v}.

In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.

7 0
3 years ago
A steel tank of weight 600 lb is to be accelerated straight upward at a rate of 1.5 ft/sec2. Knowing the magnitude of the force
VikaD [51]

Answer:

a) the values of the angle α is 45.5°

b) the required magnitude of the vertical force, F is 41 lb

Explanation:

Applying the free equilibrium equation along x-direction

from the diagram

we say

∑Fₓ = 0

Pcosα - 425cos30° = 0

525cosα - 368.06 = 0

cosα = 368.06/525

cosα = 0.701

α = cos⁻¹ (0.701)

α = 45.5°

Also Applying the force equation of motion along y-direction

∑Fₓ = ma

Psinα + F + 425sin30° - 600 = (600/32.2)(1.5)

525sin45.5° + F + 212.5 - 600 = 27.95

374.46 + F + 212.5 - 600 = 27.95

F - 13.04 = 27.95

F = 27.95 + 13.04

F = 40.99 ≈ 41 lb

8 0
4 years ago
Two blocks are the same size one block has a higher temperature than the other. Which describes the thermal energy of these bloc
shepuryov [24]
The block that has a higher temperature describes the thermal energy of these blocks. Thermal energy is a measure of internal energy - therefore, the block with the higher temperature has more internal energy than the block with the lower temperature, meaning it's thermal energy is greater. 
8 0
3 years ago
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