A sky diver jumps from a reasonable height above the ground. The air resistance she experiences is proportional to her velocity,
and the constant of proportionality is k = 0.19. It can be shown that the downward velocity of the sky diver at time t is given by v(t) = A(1 − e^-kt) where t is measured in seconds and v(t) is measured in feet per second (ft/s). Suppose A = 64. (a) Find the initial velocity of the sky diver.
(b) Find the velocity after 5 s and after 15 s. (Round your answers to one decimal place.) ...?
and for b it will be </span><span>(5)=64(1−<span>e<span>(−0.19)(5)</span></span>)</span><span>, and likewise for t=15. You just need to throw it in a calculator.</span>
The most important thing to remember about parabolic motion in physics is that when an object reaches its max height, the velocity right there at the highest point is 0. Use this one-dimensional motion equation to solve this problem:
v = v₀ + at and filling in:
0 = v₀ + (-9.8)(4.0) **I put in 4.0 for time so we have more than just 1 sig fig here**
<span>D. Convection occurs when heated particles of a material flow toward areas having less thermal energy. This movement of particles can only occur in gases and liquids, not solids.</span>
When brougth close to the charged sphere A, as charges can move freely in a conductor, a charge equal and opposite to the one on the sphere A, appears on the sphere B surface facing to the sphere A.
As sphere B must remain neutral (due to the principle of conservation of charge) an equal charge, but of opposite sign, goes to the surface also, on the opposite part of the sphere.
If sphere A is removed, a charge movement happens in the sphere B, in such a way, that no net charge remains on the surface.
If in such state, if the sphere B (assumed again uncharged completely, without any local charges on the surface), is touched by an initially uncharged sphere C, due to the conservation of charge principle, no net charge can be built on sphere C.
