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ivann1987 [24]
3 years ago
15

A sky diver jumps from a reasonable height above the ground. The air resistance she experiences is proportional to her velocity,

and the constant of proportionality is k = 0.19. It can be shown that the downward velocity of the sky diver at time t is given by v(t) = A(1 − e^-kt) where t is measured in seconds and v(t) is measured in feet per second (ft/s). Suppose A = 64.
(a) Find the initial velocity of the sky diver.
(b) Find the velocity after 5 s and after 15 s. (Round your answers to one decimal place.) ...?
Physics
1 answer:
ch4aika [34]3 years ago
7 0

The initial velocity of the sky diver would be t=0. So put that into the equation:

<span>v(0)=64(1−<span>e<span>(−0.19)(0)</span></span>)

and for b it will be
</span><span>(5)=64(1−<span>e<span>(−0.19)(5)</span></span>)</span><span>, and likewise for t=15. You just need to throw it in a calculator.</span>

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