Answer:
The minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.
Explanation:
Given;
wavelength of light, λ = 600 nm
The minimum thickness of the soap bubble for destructive interference to occur is given by;
where;
n is refractive index of soap film = 1.33
Therefore, the minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.
Computer simulation is useful because it helps in the prediction of what will likely happen in the future using data from past events.
<h3>What is computer simulation?</h3>
- This is the use of computer models to represents a hypothetical scenarios that are likely to be obtained in the real world.
Computer simulations are useful in studying phenomena in the universe because they help us to achieve the followings;
- It helps in the prediction of what will likely happen in the future using data from past events.
- It saves cost and time of carrying out actual experiments.
- It can help prevent a disaster that may occur in the future.
Learn more about computer simulations here: brainly.com/question/22214039
Sound source is at rest, you are moving with velocity v, f = frequency, c = speed of sound:
f = f0(1 + v/c)
115 = 100(1 + v/343)
115 = 100 + 100v/343
15 = 100v/343
v = 15*343/100
<span>
v = 51,45 m/s </span>
Intensity:
Decibels
Amplitude:
Meters
Frequency: Hertz
<u>Explanation:</u>
The Wave is not visible to eyes and they can easily propagate through vacuum. the average power travelling at a given period of time in a space is the intensity. Decibels is the measure of intensity. it is measured in the decibel scale. The wave's strength and the intensity gives the amplitude of wave. It is measured using meters.
The wave's amplitude and the energy has a direct proportionality. The number occurrence of wave cycles per second refers to the frequency of wave. it is measured in hertz. it is also measured as the number of cycles that occurs per second.
Hi there! :)
Reference the diagram below for clarification.
1.
We must begin by knowing the following rules for resistors in series and parallel.
In series:
In parallel:
We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.
Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
2.
We can use Ohm's law to solve for the current in the circuit.
3.
For resistors in series, both resistors receive the SAME current.
Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.
In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is <u>3A for each 10Ω resistor</u>.
4.
Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.
