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vichka [17]
3 years ago
5

A tennis player standing 12.6 m from the net hits the ball at 3.18° above the horizontal. To clear the net, the ball must rise a

t least 0.362 m. If the ball just clears the net at the apex of its trajectory, how fast was the ball moving when it left the racket?
Physics
1 answer:
SOVA2 [1]3 years ago
3 0
At the vertex, it's vertical velocity is 0, since it has stopped moving up and is about to come back down, and its displacement is 0.33m.
So we use v² = u² + 2as (neat trick I discovered just then for typing the squared sign: hold down alt and type 0178 on ur numpad wtih numlock on!!!) ANYWAY.......
We apply v² = u² + 2as in the y direction only. Ignore x direction.
IN Y DIRECTION:
v² = u² + 2as
0 = u² - 2gh
u = √(2gh) (Sub in values at the very end)
So that will be the velocity in the y direction only. But we're given the angle at which the ball is hit (3° to the horizontal). So to find the velocity (sum of the velocity in x and y direction on impact) we can use: sin 3° = opposite/hypotenuse = (velocity in y direction only) / (velocity)
So rearranging,
velocity = (velocity in y direction only) / sin 3°
= √(2gh)/sin 3°
= (√(2 x 9.8 x 0.33)) / sin 3°
= 49 m/s at 3° to the horizontal
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A solid disk of mass 2 kg and radius 2 m is given a horizontal push of 20N at a point .3 m above its center. a. What is the mini
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\mu_s=1.0205

Explanation:

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<em>For the condition of no slip the force of  static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

\therefore F

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An ocean wave traveling in one direction has a wavelength of 1.0 m and a frequency of 1.25 Hz. Take the direction of wave propag
aliina [53]

Answer:

a) v=1*1.25=1.25\: m/s

b) y(x,t)=2sin(2\pi( x-1.25 t)  

c) y(3,10)=1.73 m    

Explanation:

a) The speed of a wave is given by the following equation:

v=\lambda f

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b) The harmonic wave has the following equation:

y=Asin(kx-\omega t)

A is the amplitude (2 m)

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ω is the angular frequency (2πf)

y(x,t)=2sin(2\pi x-2\pi*1.25 t)  

y(x,t)=2sin(2\pi( x-1.25 t)  

c) Here we need to find the heigth at x=3 m and t =10 s, so we need to find y(3,10).

y(3,10)=2sin(2\pi(3-1.25*10)

y(3,10)=2sin(2\pi(3-1.25*10)              

y(3,10)=1.73 m              

I hope it helps you!

 

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