Answer:
T1 = 130N, T2 = 370N
Explanation:
In order for the system to be at rest, the sum of all forces must be zero and the torque around a point on the beam must be zero.
1. forces:
Let tension in rope 1 be T1 and in rope 2 be T2:
ma = T1 + T2 - 100N - 400N = 0
(1) T1 + T2 = 500N
2. torque around the center point of the beam:
τ = r x F = 5*T1 + 3*400N - 5*T2 = 0
(2) T1 - T2 = -240N
Solving both equations:
T1 = 130N
T2 = 370N
Answer:
The the coefficient of kinetic friction between the horizontal surface and the block is 0.536.
Explanation:
Given that,
Spring constant = 105 N/m
Mass of block = 2.00 kg
Compress = 0.100 m
Distance = 0.250 m
We need to calculate the coefficient of kinetic friction
Using relation between friction force and restoring force
Put the value into the relation
Hence, The the coefficient of kinetic friction between the horizontal surface and the block is 0.536.