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Verizon [17]
4 years ago
8

One property that makes electromagnetic waves differ from other types of waves is that they can

Physics
1 answer:
Flauer [41]4 years ago
5 0
travel through a vacuum at the speed of light. Other waves need a medium; sound waves need molecules that vibrate.
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What is the difference between weight and mass? mass and weight are both intrinsic properties of an object. if you multiply the
MatroZZZ [7]

if you multiply the mass of an object by the acceleration due to gravity, you will obtain the object's weight. mass is an intrinsic property of matter


looks like a good answer ...

4 0
3 years ago
WILL GET BRAINLIEST IF CORRECT!!!!!!!
fredd [130]

Answer:

The answer is letter B, absorb.

Explanation:

Heat travels through three different ways: radiation,conduction and convection.

Radiation- this happens when heat moves as energy waves (infrared waves) directly from its source to something.

Conduction- heat passes directly from one object to another through the touching of surfaces.

Convection- this occurs when warmer areas of a liquid or gas rise to cooler areas in the liquid or gas.

The transfer of heat in the situation above is an example of "thermal radiation." The campfire carries light energy through the fire. These consists of electromagnetic waves (most of these are infrared light). These waves (radiation) carry energy, which is then converted to heat once it hits another object that absorbs it. In the case above, once the hands absorbs the energy, it then warms up. This happened because the hands are placed <u><em>near the campfire.</em></u> Placing the hands near the campfire is important because air is a poor thermal conductor.

Thus, the answer above is letter B, absorb.

3 0
4 years ago
The sound intensity from a jack hammer breaking concrete is 2.0W/m2 at a distance of 2.0 m from the point of impact. This is suf
kupik [55]

Answer:

(a) I_{1}=3.2*10^{-3}W/m^{2}

(b) \beta =95dB

Explanation:

Given data

Distance r₁=50 m

Distance r₂=2 m

Intensity I₂=2.0 W/m²

To find

(a) The Sound Intensity I₁

(b) The Sound Intensity level β

Solution

For (a) the Sound Intensity I₁

\frac{I_{1} }{I_{2}}=\frac{(r_{2})^{2}  }{(r_{1})^{2} }\\I_{1} =I_{2}(\frac{(r_{2})^{2}  }{(r_{1})^{2} })\\I_{1}=(2.0W/m^{2} )(\frac{(2m)^{2}  }{(50m)^{2} })\\I_{1}=3.2*10^{-3}W/m^{2}

For (b) the Sound Intensity level β

The Sound Intensity level β is calculated as follow

\beta =(10dB)log_{10}(\frac{I}{I_{o} } )\\\beta  =(10dB)log_{10}(\frac{3.2*10^{-3}W/m^{2}  }{1.0*10^{-12} W/m^{2} } )\\\beta =95dB

8 0
3 years ago
A&amp;P I need helppp <br> plspls
katrin2010 [14]

Answer:

c

Explanation:

6 0
3 years ago
A very long thin wire carries a uniformly distributed charge, which creates an electric field. The electric field is (2300 N/C ,
Leto [7]

Answer:

λ= 5.24 × 10 ⁻² nC/cm

Explanation:

Given:

distance r = 4.10 cm = 0.041 m

Electric field intensity E = 2300 N/C

K = 9 x 10 ⁹ Nm²/C

To find λ = linear charge density = ?

Sol:

we know that E= 2Kλ / r

⇒ λ = -E r/2K         (-ve sign show the direction toward the wire)

λ = (- 2300 N/C × 0.041 m) / 2 ×  9 x 10 ⁹ Nm²/C

λ = 5.24 × 10 ⁻⁹ C/m

λ = 5.24 nC/m = 5.24 nC/100 cm

λ= 5.24 × 10 ⁻² nC/cm

3 0
3 years ago
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