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3 years ago

What is the most important characteristic in determining an element’s properties?

Chemistry

1 answer:

lozanna [386]3 years ago

4 0

The number of electrons. The valence (outer) shell is particularly important.

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How do you determine the correct subscripts in a chemical formula

VMariaS [17]

BY CHECKING THE REACTIVITY OF AN ELEMENT WHICH IS MOST REACTIVE OR NOT AND YOU STUDY TYPE OF CHEMICAL REACTION IN 1 CH AND YOU CHECK THE REACTIVITY OF ELEMENTS IN 3 CH METALS AND NON METALS PAGE NO 45 IN NCERT BOOK

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3 years ago

A sample of gas has an initial volume of 3.62 L at a pressure of 0.987 atm. If the volume of the gas decreases to 2.50 L, what w

statuscvo [17]

Answer:

0.033 atm

Explanation:

PV=nRT

rule of 1 for T and n

P= nRT/V

P= 1(.08206)1)/ 2.50

0.033 atm = pressure

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3 years ago

Chem. Assignment I need help...with answers 1-6 thanks

Anna11 [10]

Answer:

1. an educated guess

2. data

3. what changes in experiment

4. what stays the same in both groups

5. the group where nothing changes, normal

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3 years ago

Define a fluid very sort answer

Ganezh [65]

Answer:

A fluid is a medium that has a defined mass and volume, but no fixed shape, at a constant temperature and pressure. This may include gases, liquids, plasmas, and to some extent plastic solids. A fluid can flow and deform, preventing it from carrying loads in a static equilibrium. A fluid is always compressible and internal frictional forces always occur due to the viscosity of the fluid.

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3 years ago

WILL MARK BRAINLIEST!!!!

Lyrx [107]

Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Compounds
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})$
[DA] Divide [Cancel out units]: $\displaystyle 5.7015 \ mol \ K_2SO_4$

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

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3 years ago