Answer:
3
Explanation:
NaCl + AgNO₃ ———> NaNO₃ + AgCl.
Firstly, we will need to calculate the number of moles of AgCl produced. That is equal to the mass produced divided by the molar mass of AgCl.
The molar mass of AgCl = 108 + 35.5 = 143.5g/mol
The number of moles is thus 1.32/143.5 = 0.0092 moles
Since silver nitrate and silver chloride contains one atom of silver, it is only possible that their mole ratios are equal. Hence we say that 0.0092 moles of silver nitrate hydrate was dissolved.
Now we go on to calculate the molar mass of the silver nitrate hydrate.
The molar mass is simply the mass divided by the number of moles.
That is 2.06/0.0092 = 223.9 = 224g/mol
We can now calculate the value of x from here.
AgNO3.xH2O
(108 + 14 + 48) + x(2+ 16) = 224
170 + 18x = 224
18x = 224 - 170 = 54
18x = 54
x = 54/18 = 3
