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allsm [11]
3 years ago
6

describe a general rule for predicting the motion of an object that is being pushed or pulled by unbalanced forces?

Chemistry
1 answer:
7nadin3 [17]3 years ago
6 0

<span>7th grade activities</span>

Force and Motion

(with Work)

 

2010-2011

 

 

<span>
</span>

Outline of Topics:

<span>1.     </span><span>Describing Motion: Graphing, Speed and Velocity  </span>

<span>2.   Describing Motion: Changing Velocity </span>

<span>3.   Forces, Their Sizes and Direction </span>

<span>4.   Force and Mass </span>

<span>5.   Its a grave matter: gravity and inertia </span>

<span>6.   Weight and Mass </span>

<span>7.   All work and no play: Work and Energy </span>

 

Appendices

<span>1:  7th Grade Vocabulary Related to Force and Motion</span>

<span>2:  Motion Detector Directions</span>

<span>3:  Day 1 Graphs with Focus Question at the End</span>

<span>4:  Day 1 Data Collection Sheet </span>

<span>5:  Day 2 Student Problem Sheet</span>

<span>6:  Day 2 Second Set of Problems</span>

<span>7:  Day 2 Graphs for is the Velocity Changing</span>

<span>8:  Day 3 Student Tables with Questions</span>

<span>9:  Day 4 Frame for Science Notebook</span>

<span>10:  Day 5 Skateboard Prediction and Actual Sheets</span>

<span>11:  Day 6 Data Table</span>

12: Day 7 Student Handout

13: Day 7 Force Arrows

<span>14:  Day 8 Data Analysis</span>

<span>15:  Uncovering Student Ideas in Physical Science probes</span>

<span>16:  National Enquirer advertisements</span>

<span>17: Excerpt from Joy Hakim’s The Story of Science: Newton at the Center, pages 172-183</span>

<span>18:  Directions for converting You Tube videos to another media file</span>

 

<span>
</span>

<span>First topic:  Describing motion</span>

A three-day exercise

Learning goals

<span>Reviewed from 6th grade (day 1): </span>

I can interpret a position versus time line graph to determine types of one-dimensional motion of an object.

I can draw a position versus time line graph given appropriate data.

I can represent changes in motion in a variety of ways, including words, motion arrows, graphs, and by acting out.

(Day 2) I can use the information in a position vs. time graph to determine the speed of an object.

<span>New for 7th grade: I can define velocity.</span>

(Day 3) I can distinguish between speed and velocity.

 

Topic Word Bank

<span> <span><span> <span> Speed </span> <span> Motion </span> </span> <span> <span> Velocity </span> <span> Direction </span> </span> <span> <span> Position </span> <span> Graph </span> </span> <span> <span> Distance </span> <span> Vertical </span> </span> <span> <span> Time </span> <span> Horizontal </span> </span> <span> <span> Rate of change </span> <span> Representation </span> </span> <span> <span> Slope </span> <span> <span>             Negative</span> </span> </span> <span> <span>   </span> <span> <span>             Positive</span> </span> </span> </span></span>

 

<span> <span><span> <span> Sequence of Experiences </span> </span> <span> <span> Day 1: Interpretation of a Position/Time Graph </span> <span> Pairs and whole group </span> <span> 10 minutes </span> </span> <span> <span> Day 1: Creation of a Position/Time Graph </span> <span> Lab groups and whole group </span> <span> 25 minutes </span> </span> <span> <span> Day 1: Making Sense of Multiple Representations </span> <span> Whole Group </span> <span> 10 minutes </span> </span> <span> <span> Day 2: Calculating Speed </span> <span> Pairs and whole group </span> <span> 23 minutes </span> </span> <span> <span> Day 2: Differentiating Speed and Velocity </span> <span> Pairs and whole group </span> <span> 18 minutes </span> </span> <span> <span> Day 2: Exit Slip </span> <span> Individually </span> <span> 5 minutes </span> </span> <span> <span> Day 3 Intro </span> <span> Whole class </span> <span> 3 minutes </span> </span> <span> <span> Day 3:Collecting Initial Data </span> <span> In pairs </span> <span> 12 minutes </span> </span> <span> <span> Day 3:Interpreting Data Parts 1 and 2 </span> <span> In pairs, then groups of 4 </span> <span> 20 minutes </span> </span> <span> <span> Day 3: Student Challenge </span> <span>   </span> <span>   </span> </span> <span> <span> Day 3: Class Discussion </span> <span> Whole class </span> <span> 7 minutes </span> </span> <span> <span> Day 4: Intro </span> <span>   </span> <span>   </span> </span> <span> <span> Day 4:Interpreting Data Parts 3, 4 and 5 </span> <span> Whole class </span> <span>   </span> </span> <span> <span> Day 4: Processing Information </span> <span> Individual and Paired </span> <span>   </span> </span> <span> <span> Day 4: Class Discussion </span> <span> Whole Class </span> <span>   </span> </span> <span> <span> Day 4: Exit Slip </span> <span> Individually </span> <span> 3 minutes </span> </span> </span></span> <span>
</span>

Day 1  <span>Focus Question:  What can be learned from different representations of motion?</span>

Materials and Preparation:

For the class:

<span><span><span><span /></span></span></span>

<span />





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swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

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3 years ago
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The highest atom economy

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<h3>Further explanation</h3>

Given

The reaction for the production of CO₂

Required

The highest atom economy

Solution

In reactions, there are sometimes unwanted products that can be said to be a by-product or a waste product. Meanwhile, the desired product can be said to be a useful product, which can be shown as the atom economy

of the reaction

the higher the atomic economy value of a reaction, the smaller the waste/ byproducts produced, so that less energy is wasted

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So a reaction that only produces one product will have the highest atomic value, namely the reaction in option C

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Answer:

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Explanation:

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