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2 years ago

Can you walk on the moon

Physics

2 answers:

morpeh [17]2 years ago

7 0

You can. But the gravity on the moon is 1/6th the gravity on Earth. This means 300 lbs man would only weigh 50 lbs.

Anastasy [175]2 years ago

4 0

Yes u can walk on the moon

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A 70 kg man is walking at a speed of 2 m/s. What is his Kinetic Energy?

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140 Jules. Is the correct answer

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3 years ago

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Which condition must be met in order for an equation to be balanced?

vitfil [10]

Answer:

There must be an equal amount of each element on both sides of the equation. Hope this helps and please marks as the brainliest.

Explanation:

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2 years ago

The mean diameters of Mars and Earth are 6.9 ✕ 103 km and 1.3 ✕ 104 km, respectively. The mass of Mars is 0.11 times Earth's mas

Roman55 [17]

Answer:

(a) Ratio of mean density is 0.735

(b) Value of g on mars 0.920 $m,/sec^2$

Explanation:

We have given radius of mars $R_{mars}=6.9\times 10^3km=6.9\times 10^6m$ and radius of earth $R_{E}=1.3\times 10^4km=1.3\times 10^7m$

Mass of earth $M_E=5.972\times 10^{24}kg$

So mass of mars $M_m=5.972\times\times 0.11 \times 10^{24}=0.657\times 10^{24}kg$

Volume of mars $V=\frac{4}{3}\pi R^3=\frac{4}{3}\times 3.14\times (6.9\times 10^6)^3=1375.357\times 10^{18}m^3$

So density of mars $d_{mars}=\frac{mass}{volume}=\frac{0.657\times 10^{24}}{1375.357\times 10^{18}}=477.69kg/m^3$

Volume of earth $V=\frac{4}{3}\pi R^3=\frac{4}{3}\times 3.14\times (1.3\times 10^7)^3=9.198\times 10^{21}m^3$

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3 years ago

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Sphinxa [80]

Answer:

The right solution is "165.8 nm".

Explanation:

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n = 1.81

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λ = 600 nm

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⇒ $t=\frac{\lambda}{2\times n}$

By putting the values, we get

$=\frac{600}{2\times 1.81}$

$=165.8 \ nm$

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2 years ago

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The Equivalent resistance is :

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