Answer:
<em>The tension in the web is 0.017738 N</em>
Explanation:
<u>Net Force</u>
The net force exerted on an object is the sum of the vectors of each individual force applied to an object.
If the net force equals 0, then the object is at rest or moving at a constant speed.
The spider described in the question is hanging at rest. It means the sum of the forces it's receiving is 0.
A hanging object has only two forces: The tension of the supporting string (in our case, the web) and its weight. If the object is in equilibrium, the tension is numerically equal to the weight:
T=W=m.g
The mass of the spider is m=1.81 gr = 0.00181 Kg, thus the tension is:
The tension in the web is 0.017738 N
Answer:
Explanation:
Given two mass on an incline code and and an angle of inclination . . Assume that is the weight being pulled up and the hanging weight.
-The equations of motion from Newton's Second Law are:
where a is the acceleration.
#Substituting for (tension) gives:
#and solving for
which is the system's acceleration.
Answer:
64 J
Explanation:
The potential energy change of the spring ∆U = -W where W = work done by force, F.
Now W = ∫F.dx
So, ∆U = - ∫F.dx = - ∫Fdxcos180 (since the spring force and extension are in opposite directions)
∆U = - ∫-Fdx
= ∫F.dx
Since F = 40x - 6x² and x moves from x = 0 to x = 2 m, we integrate thus, ∆U = ∫₀²F.dx
= ∫₀²(40x - 6x²).dx
= ∫₀²(40xdx - 6x²dx)
= ∫₀²(40x²/2 - 6x³/3)
= ∫₀²(20x² - 2x³)
= [20x² - 2x³]₀²
= [(20(2)² - 2(2)³) - (20(0)² - 2(0)³)
= [(20(4) - 2(8)) - (0 - 0))
= [80 - 16 - 0]
= 64 J
Answer:
at n= 3 λ = 656 nm
at n= 2 λ = 121.58 nm
Explanation:
Given details
transition of hydrogen atom from n = 2 to n = 3 state
Difference in energy between n = 3 state and n = 2 state :
so, energy of photon is given as
So solve for wavelength
so, λ
=
= 656 nm
for second transition,
energy transmitted is given asΔE
and it is calculated as
E = 1.635*10-18 J solving for wavelength in ENERGY equation we get
so, m
= 121.58 nm
G
has the SI units
m
3
k
g
⋅
s
2