0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary to reach stoichiometric quantities with cacl2.
<h3>Explanation:</h3>
Based on the reaction
CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃
1 mole of CaCl₂ reacts per mole of Na₂CO₃
we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g
- We must calculate the moles of CaCl2•2H2O using its molar mass (147.0146g/mol) in order to answer this issue.
- These moles, which are equal to moles of CaCl2 and moles of Na2CO3, are required to obtain stoichiometric amounts.
- Then, we must use the molar mass of Na2CO3 (105.99g/mol) to determine the mass:
<h3>
Moles CaCl₂.2H₂O:</h3>
1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂
Moles Na₂CO₃:
0.0102 moles Na₂CO₃
Mass Na₂CO₃:
0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present
Therefore, we can conclude that 0.0102 moles Na₂CO₃ is necessary.to reach stoichiometric quantities with cacl2.
To learn more about stoichiometric quantities visit:
<h3>
brainly.com/question/28174111</h3>
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Answer:
Pb3O4 + 4H2 → 3Pb + 4H2O
Explanation:
Pb3O4
Tritium - H2
Molar Mass of H2 Bond Polarity H-3 Hydrogen-3 3H T
Products
Lead - Pb
Molar Mass of Pb Plumbum Element 82 Bulk Lead
Water - H2O
Molar Mass of H2O Oxidation Numbers of H2O Dihydrogen Monoxide Dihydridooxygen Hoh Hydrogen Hydroxide Dihydrogen Oxide Oxidane Hydrogen Oxide Pure Water
Answer: Option (b) is the correct answer.
Explanation:
Polarity is defined as the development of partial charges on the atoms of a molecule.
Whereas polarizability is defined as the ability or measure of how readily an electron cloud is able to get distorted. More is the polarizability more will be the electron is distorted in nature.
A dipole moment is defined as the measurement of the separation of two opposite electrical charges.
Thus, we can conclude that when the electron cloud of a molecule is easily distorted, the molecule has a high polarizability.