<span>There are 34 hydrogen atoms.
</span>
Answer:
wax i think
Explanation:
i don't understand a thing you just wrote
The higher the current, the more likely it is lethal. Since current is proportional to voltage when resistance is fixed (ohm's law), high voltage is an indirect risk for producing higher currents.
<u>Answer: </u>The volume of the solution is 85.7 mL
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
We are given:
Molarity of solution = 0.600 M
Given mass of
= 12.00 g
We know, molar mass of ![BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol](https://tex.z-dn.net/?f=BaSO_4%3D%5B%281%5Ctimes%20137.33%29%2B%281%5Ctimes%2032.07%29%2B%284%5Ctimes%2016%29%5D%3D233.4g%2Fmol)
Putting values in equation 1, we get:

The rule of significant number that is applied for the problems having multiplication and division:
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.
Hence, the volume of the solution is 85.7 mL
pH of the acetyl choline solution before incubation = 7.65
![[H_{3}O^{+}]=10^{-7.65}=2.24*10^{-8}M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3D10%5E%7B-7.65%7D%3D2.24%2A10%5E%7B-8%7DM)
pH of the solution after incubation = 6.87
![[H_{3}O^{+}]=10^{-6.87}=1.35*10^{-7}M](https://tex.z-dn.net/?f=%5BH_%7B3%7DO%5E%7B%2B%7D%5D%3D10%5E%7B-6.87%7D%3D1.35%2A10%5E%7B-7%7DM)
The difference in concentration of hydronium ion before and after incubation
=
-
=
This difference in hydronium ion concentration can be attributed to the increase in the concentration of acetic acid, which is formed when acetylcholine is hydrolyzed by acetycholinesterase. The mole ratio of acetylcholine to acetic acid is 1:1.
Therefore the moles of acetylcholine = 