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sashaice [31]
3 years ago
6

When the stabilized state of an equilibrium system is altered, further chemical reactions begin until a new equilibrium is reach

ed.
a. True
b. False?
Chemistry
2 answers:
Nezavi [6.7K]3 years ago
7 0
The answer is a. True. This is also known as the Le Chatelier's principle or The Equilibrium Law which states that if a chemical reaction is at equilibrium and then experiences changes in the condition of the reaction such as changes in concentration, pressure, or temperature of products or reactants, the system will naturally shift to achieve a new equilibrium state.
Anvisha [2.4K]3 years ago
4 0

Answer:

T

Explanation:

I took the test and got it right

When the stabilized state of an equilibrium system is altered, further chemical reactions begin until a new equilibrium is reached.

True or False

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The amount of 217 mg of an isotope is given by A(t) = 217 € -0.0171, where t is time in years since the initial amount of 217 mg
Maru [420]

The amount left after 20 years = 154.15 mg

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles  

The decay formula for isotope :

\tt \large{\boxed{\bold{A(t)=217e^{-0.0171t}}}

Then for t=20 years, the amount left :

\tt A(t)=217e^{-0.0171\times 20}\\\\A(t)=154.15~mg

4 0
3 years ago
Read 2 more answers
A battery can provide a current of 4.60 A at 3.40 V for 2.50 hr. How much energy (in kJ) is produced? 1st attempt kJ Energy
Lunna [17]

Answer:

The energy produced equals 140.760 kJ

Explanation:

The relation between power, current and voltage is

Power=Current\times Voltage

Applying the given values in the relation above we get

Power=4.60\times 3.40=15.64W

Now Since Power=\frac{Energy}{Time}\\\\Energy=Power\times Time

Again applying the calculated values we get

Energy=15.64\times 2.50\times 3600=140760Joules=140.76kJ

4 0
3 years ago
What do you think might be different between fat molecules and carbohydrate and protein molecules?
dimulka [17.4K]

Answer:

Long answer

Proteins are the building blocks of the body, each and every organ muscle and skin and cells are made of proteins. They can also be used for providing energy to the body in a state where other energy sources aren't available.

Fats are stored energy blocks which can be used by the body at its own convenience whenever there is a deficit of energy in the body. They can also be directly burnt to give energy in cases where energy needs of the body are not met by dietary intake

Carbohydrates are the most convenient and preferable source of energy in the body and are easily converted to give out immidiate energy to the body, excess carbohydrates can be converted into fats and stored for later usage as and when required by the body.

Proteins, fats and carbohydrates have many secondary functions and roles in the human body. If you are keen to know anything more specific feel free to ask.

<h3>Short answer :</h3>

Fats are used for energy after they are broken into fatty acids. Protein can also be used for energy, but the first job is to help with making hormones, muscle, and other proteins.

7 0
2 years ago
Read 2 more answers
A sample of argon gas has a volume of 73 mL at a pressure of 1.20 atm and a temperature of 112 degrees Celsius. What is the fina
NeX [460]

Answer:

V₂ → 106.6 mL

Explanation:

We apply the Ideal Gases Law to solve the problem. For the two situations:

P . V = n . R . T

Moles are still the same so → P. V / R. T = n

As R is a constant, the formula to solve this is: P . V / T

P₁ . V₁ / T₁ = P₂ .V₂ / T₂   Let's replace data:

(1.20 atm . 73mL) / 112°C = (0.55 atm . V₂) / 75°C

((87.6 mL.atm) / 112°C) . 75°C = 0.55 atm . V₂

58.66 mL.atm = 0.55 atm . V₂

58.66 mL.atm / 0.55 atm = V₂ → 106.6 mL

3 0
3 years ago
How many moles of oxygen are required to react with 12 moles of FeS2?
Radda [10]
19 moles of O2 probably
3 0
2 years ago
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