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2 years ago

What was the hiker's average velocity during part C of the hike?

Chemistry

1 answer:

umka2103 [35]2 years ago

6 0

Answer:

0.13 km/min west

Explanation:

I just did the test.

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Hydrogen can be extracted from natural gas according to the following equilibrium.

antiseptic1488 [7]

Answer:

2.16x10⁻²

Explanation:

First, let's find out the molar concentrations of the reactants. The molar mass of CH4 is 16 g/mol, and of CO2 is 44 g/mol. The number of moles is the mass divided by the molar mass:

nCH4 = 24.0/16 = 1.5 moles

nCO2 = 88.0/44 = 2 moles

The concentration is the number of moles divded by the volume, thus:

[CH4] = 1.5/1 = 1.50 M

[CO2] = 2/1 = 2.00 M

For the equilibrium reaction, let's do an equilibrium chart:

CH4(g) + CO2(g) ⇄ 2CO(g) + 2H2(g)

1.50 2.00 0 0 Initial

-x -x +2x +2x Reacts (stoichiometry is 1:1:2:2)

1.50-x 2.00-x 2x 2x Equilibrium

As sateted in problem, [CH4] = 2.70*[CO]

1.50 - x = 2.70*2x

1.50 - x = 5.4x

6.4x = 1.50

x = 0.2344

Thus, at equilibrium:

[CH4] = 1.50 - 0.2344 = 1.2656 M

[CO2] = 2.00 - 0.2344 = 1.7656 M

[CO] = 2*0.2344 = 0.4688 M

[H2] = 2*0.2344 = 0.4688 M

The equilibrium constant is the multiplication of the concentrations of the products elevated by their coefficients, divided by the multiplication of the concentration of the reactants elevated by their coefficients.

K = ([CO]²*[H2]²)/([CH4]*[CO2])

K = (0.4688²*0.4688²)/(1.2656*1.7656)

K = 0.0483/2.2345

K = 2.16x10⁻²

7 0

2 years ago

The equilibrium constant, K, for the following reaction is 5.10X10 at 548 K. NH_CH(s) 2 NH3(E) + HC1(2) Calculate the equilibriu

Serga [27]

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = $K_c=5.10\times 10^{-6}$

Moles of ammonium chloride = 0.573 mol

Concentration of ammonium chloride = $\frac{0.573 mol}{1.00 L}=0.573 M$

$NH_4HCl(s)\rightleftharpoons 2 NH_3(g) + HCl(g)$

Initial: 0.573 0 0

At eq'm: (0.573-x) x x

We are given:

$[NH_4Cl]_{eq}=(0.573-x)$

$[HCl]_{eq}=x$

$[NH_3]_{eq}=x$

Calculating for 'x'. we get:

The expression of $K_{c}$ for above reaction follows:

$K_c=\frac{[HCl][NH_3]}{[NH_4Cl]}$

Putting values in above equation, we get:

$5.10\times 10^{-6}=\frac{x\times x}{(0.573-x)}$

$2.9223\times 10^{-6}-5.10x\times 10^{-6}=x^2$

$x^2-2.9223\times 10^{-6}+(5.10\times 10^{-6})x=0$

On solving this quadratic equation we get:

x = 0.01707 M

The equilibrium concentration of HCl is 0.01707 M.

3 0

3 years ago

How many electrons can each individual orbital hold?

Hatshy [7]

Answer:

Orbitals of equal energy are each occupied by one electron before any orbital is occupied by a second electron, and all electrons in singly occupied orbitals must have the same spin state. Noble-gas configuration refers to an outer main energy level occupied, in most cases, by eight electrons.

Explanation:

I hope this helps you.

3 0

2 years ago

Read 2 more answers

The Periodic Table: Tutorial

Advocard [28]

Answer:

There is nothing here for us to help you with.

Explanation:

3 0

3 years ago

Put this equation into word form.

Mars2501 [29]

Answer:

Explanation:

symbol of postassium is k and there is no symbol k. so i guess no2

7 0

2 years ago