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Goryan [66]
3 years ago
14

A proton is propelled at 4×106 m/s perpendicular to a uniform magnetic field. 1) If it experiences a magnetic force of 4.8×10−13

N, what is the strength of the magnetic field? (Express your answer using two significant figures.)
Physics
1 answer:
tia_tia [17]3 years ago
8 0

Answer:

B = 0.75 T

Explanation:

As we know that the force on a moving charge in magnetic field is given by the formula

F = qvB

here we have

B = \frac{F}{qv}

here we know that

F = 4.8 \times 10^{-13} N

q = 1.6 \times 10^{-19} C

v = 4 \times 10^6 m/s

now from above equation we have

B = \frac{4.8 \times 10^{-13}}{(1.6 \times 10^{-19})(4 \times 10^6)}

B = 0.75 T

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Answer:

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A college student holds a pail full of water by the handle and whirls it around in a vertical circle at a constant speed. The ra
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The minimum speed of the water must be 3.4 m/s

Explanation:

There are two forces acting on the water in the pail when it is at the top of its circular motion:

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  • The normal reaction, N also acting downward

Since the water is in circular motion, the net force must be equal to the centripetal force, so:

N+mg=m\frac{v^2}{r}

Where:

g=9.8 m/s^2

v is the speed of the pail

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The water starts to spill out when the normal reaction of the pail becomes zero:

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When this occurs, the equation becomes:

mg=m\frac{v^2}{r}\\v=\sqrt{gr}

And substitutin the values of g and r, we find the minimum speed that the water must have in order not to spill out:

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The number of protons equals the atomic number. TRUE OR FALSE?
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Answer:

true

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A 46 g domino slides down a 30 degrees incline at a constant speed. What is the coefficient of friction?
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30

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