Answer:
Answer is D. All of the above
Answer:
<h2><u>Of moles of NH4NO3 = 16/80 i.e. 0.2 moles of Ammonium Nitrate. 1 molecule of NH4NO3 contains 1 atom of N. Hence, 1 mole of NH4NO3 would contain 1 mole of Nitrogen atoms and therefore 0.2 moles of NH4NO3 should contain 0.2 moles of Nitrogen atoms</u>.</h2>
Explanation:
The balanced chemical reaction is expressed as:
<span>8SO2 + 16H2S = 3S8 + 16H2O
We are given the initial amount of the reactants. From there, we determine the limiting reactant. We do as follows:
87.0 g SO2 ( 1 mol / 64.07 g ) = 1.36 mol SO2 ( 16 mol H2S / 8 mol SO2 ) = 2.72 mol H2S
87.0 g H2S ( 1 mol / 34.08 g ) = 2.55 mol H2S ( 8 mol SO2 / 16 mol H2S ) = 1.28 mol SO2
Therefore, the limiting reactant would be H2S. We calculate the maximum amount of S8 that can be produced from the amount of H2S.
2.55 mol H2S ( 3 mol S8 / 16 mol H2S ) ( 256.48 g / 1 mol ) = 122.63 g S8</span>
Answer: just double the recipe my dude
Explanation:
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