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Yuliya22 [10]
2 years ago
11

Jati has a sample of a solid.Suggest how he could find out weather the solid is a pure substance or a mixture of substances?

Chemistry
1 answer:
Vsevolod [243]2 years ago
5 0

Answer:

The melting point range of a substance is the temperature range from which the first crystal starts to melt, to the temperature at which the last crystal finishes melting. An impure substance is a type of mixture, so melting points can be used to find out if a substance is pure or impure.

pls mark brainiest

Explanation:

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The chemical symbol for a calcium ion is ca2 . what does the 2 symbolize
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2 stands for valency of ca ion

its +2

that it takes two electrons to complete its shell
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2 years ago
A) Devices that transfer kinetic energy have what for their source of power?
GarryVolchara [31]

Answer:

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Explanation:

4 0
3 years ago
Which missing item would complete this beta decay reaction?
madam [21]

Answer:

<h3>The answer is option A.</h3>

Hope this helps you

8 0
3 years ago
What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
Ymorist [56]

Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

6 0
2 years ago
500.0 mL of a gas is collected at 745.0 mm Hg. what what will the volume be at standard pressure
Irina-Kira [14]
This is an application of Boyle's law:
P₁V₁ = P₂V₂. we don't have to convert volume and pressure to standard forms. we can even use the pressure with mmHg
1 atm = 760 mmHg 
V₂ = P₁V₁ / P₂ = 745 x 500 / 760 = 490 ml
Note that here we assume constant temperature
6 0
3 years ago
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