A 0.11 N m torque is applied to a fan that was initially at rest. The fan has moment of inertia of 0.034 kg m2. Determine the ki
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Answer:
Maximum height of rocket = 2538.74 m
Explanation:
We have equation of motion s = ut + 0.5 at²
For first 5 seconds
s = 0 x 5 + 0.5 x 40 x 5² = 500 m
Now let us find out time after 5 seconds rocket move upward.
We have the equation of motion v = u + at
After 5 seconds velocity of rocket
v = 0 + 40 x 5 = 200 m/s
After 5 seconds the velocity reduces 9.8m/s per second due to gravity.
Time of flying after 5 seconds
Distance traveled in this 20.38 s
s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m
Maximum height of rocket = 500 +2038.74 = 2538.74 m
What you need to know is that the force is
F=ma
The force is the product of mass and acceleration
this means that the acceleration is
a=F/m
a) The force is halved?
this means that f will be
now:
a=
So the accelaration will also he halved (it's the original acceleratation divided by 2)
b) The object's mass is halved?
a=
=a=
which is the original acceleration times two!! so it will double
c) The force and the object's mass are both halved?
now we have
a=
=a=
=a=
so they will cancel each other out and the acceleration will stay the same!
F=ma
The force is the product of mass and acceleration
this means that the acceleration is
a=F/m
a) The force is halved?
this means that f will be
a=
So the accelaration will also he halved (it's the original acceleratation divided by 2)
b) The object's mass is halved?
a=
which is the original acceleration times two!! so it will double
c) The force and the object's mass are both halved?
now we have
a=
so they will cancel each other out and the acceleration will stay the same!