Answer:
Explanation:
A lava lamp consists of oil, and wax in a glass, and a heat source (a light bulb) placed underneath the glass. When the lamp is turned on the bulb gets hot. As the bulb heats up some of the heat from the bulb is transferred to the glass by radiation.
Answer: The force needed is 140.22 Newtons.
Explanation:
The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.
The force exerted on the pellet is
F = m a
In order to calculate the acceleration, given the displacement d,
![d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%5Cimplies%20a%3D%5Cfrac%7B2d%7D%7Bt%5E2%7D)
we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:
![\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}](https://tex.z-dn.net/?f=%5Coverline%7Bv%7D%3D%5Cfrac%7B1%7D%7B2%7D%28v_%7Bend%7D-v_%7Bstart%7D%29%3D%5Cfrac%7B1%7D%7B2%7D%28155-0%29%5Cfrac%7Bm%7D%7Bs%7D%3D77.5%5Cfrac%7Bm%7D%7Bs%7D)
This value can be used to determine the time for the pellet through the barrel:
![t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bd%7D%7B%5Coverline%7Bv%7D%7D%3D%5Cfrac%7B0.6m%7D%7B77.5%5Cfrac%7Bm%7D%7Bs%7D%7D%5Capprox0.00774s)
Finally, we can use the above to calculate the force:
![F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N](https://tex.z-dn.net/?f=F%20%3D%20ma%20%3D%20m%5Cfrac%7B2d%7D%7Bt%5E2%7D%20%3D%200.007kg%5Ccdot%20%5Cfrac%7B2%5Ccdot%200.6%20m%7D%7B0.00774%5E2%20s%5E2%7D%5Capprox%20140.22N)
@AL2006 had answered this before: Well, first of all, wherever you got this question from has done
a really poor job of question-writing. There are a few assorted
blunders in the question, both major and minor ones:
-- 22,500 is the altitude of a geosynchronous orbit in miles, not km.
-- That figure of 22,500 miles is its altitude above the surface,
not its radius from the center of the Earth.
-- The orbital period of a synchronous satellite has to match
the period of the Earth's rotation, and that's NOT 24 hours.
It's about 3 minutes 56 seconds less ... about 86,164 seconds.
Here's my solution to the question, using some of the wreckage
as it's given, and correcting some of it. If you turn in these answers
as homework, they'll be marked wrong, and you'll need to explain
where they came from. If that happens, well, serves ya right for
turning in somebody else's answers for homework.
The satellite is traveling a circle. The circle's radius is 26,200 miles
(not kilometers) from the center of the Earth, so its circumference
is (2 pi) x (26,200 miles) = about 164,619 miles.
Average speed = (distance covered) / (time to cover the distance)
= (164,619 miles) / day
(264,929 km)
= 6,859 miles per hour
(11,039 km)
= 1.91 miles per second
(3.07 km)
Time is being measured in days here so if you want to calculate the rate of increase after one day, substitute 1 for t in your rate equation:
dB/dt = 0.677598 cos(1.232(1))
dB/dt = 0.22
Answer:
(a) -1.18 m/s
(b) 0.84 m/s
Explanation:
(a)
The total linear momentum before the lumberjack begins to move is zero because all parts of the system are at res
From the law of conservation of momentum
m1v1+m2v2=0 hence m1v1=-m2v2 where m1 is mass of lumberjack, v1 is velocity of lumberjeck, m2 is mass of floating log, v2 is velocity of the floating log.
Substituting M1 for 103 Kg, V1 for 2.93 m/s, M2 for 255 Kg into the above equation we obtain
103Kg*2.93 m/s=-255Kg*V2
V2=-(103 kg*2.93 m/s)/255=-1.183490196 m/s
Hence V2=-1.18 m/s
(b)
For the second log
V(M1+M2)=m1v1 where V is the common velocity
V(103 Kg+255 Kg)=103 Kg*2.93 m/s
V=(103 Kg*2.93 m/s)/(103 Kg+255 Kg)=0.842988827 m/s
V=0.84 m/s