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3 years ago

A charged particle moving in a magnetic field will be deflected in a direction ____________________ to the magnetic field

2 answers:

4 0

A charged particle moving in a magnetic field will be deflected in a direction perpendicular to the magnetic field. This is the vector equation: F = m a = q v x B.

Temka [501]3 years ago

3 0

Answer:

Perpendicular

Explanation:

A charged particle moving in a magnetic field will be deflected in a direction perpendicular to the magnetic field.

The magnetic force is given by :

$F=q(v\times B)$

We know that, F = m a

$F=ma=q(v\times B)$

So, the motion of the charged particle is directly proportional to the q, v and B and also on the angle between the velocity and the magnetic field. It is maximum when the motion of charged particle is perpendicular to the magnetic field.

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What is the angle of the 2nd order bright fringe produced by two slits that are 8.25x10-5m apart if the wavelength of the incide

dexar [7]

In order to calculate the angle, we can use the formula below for a constructive interference (the interference is constructive because the fringe is bright):

$d\sin\theta=m\lambda$

Where d is the distance between the slits, m is the order of the interference and lambda is the wavelength.

So, using d = 8.25 * 10^-5, m = 2 and lambda = 4.5 * 10^-7, we have:

$\begin{gathered} 8.25\cdot10^{-5}\cdot\sin\theta=2\cdot4.5\cdot10^{-7}\\ \\ \sin\theta=\frac{9\cdot10^{-7}}{8.25\cdot10^{-5}}\\ \\ \sin\theta=1.091\cdot10^{-2}\\ \\ \theta=0.625° \end{gathered}$

Therefore the correct option is the second one.

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1 year ago

If the police are chasing a runaway car why is knowing the velocity of the car important

atroni [7]

If you only know its speed, that's not enough information to catch it. You could even chase it at DOUBLE that speed, and you'd never catch it if you were chasing in the wrong direction.

You also have to know the DIRECTION the runaway car is going, so that you can chase in the same direction.

Now that you know its speed AND direction, you know its velocity. You need that information to have any chance of catching it.

8 0

3 years ago

A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is

jasenka [17]

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, $F_{net}$ = The weight of the student + The inertia force of the slowing elevator

∴ The net force, $F_{net}$ = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

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3 years ago

1. What kind of force is the force of gravity? (1 Point) contact force

Vinil7 [7]

Answer:

luựchút tras dadats

Explanation

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3 years ago

The world's largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity fo

Arturiano [62]

Answer:

The velocity of the blades is 88.185 m/s.

Explanation:

Given;

length of the blade, r = 80 m

angular speed, ω = 1 rev per 5.7 seconds

The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);

$V = \omega r\\\\V = (\frac{1 \ rev}{5.7 \ s} \times \frac{2 \pi \ rad}{ 1 \ rev} )(80 \ m)\\\\V = 88.185 \ m/s$

Therefore, the velocity of the blades is 88.185 m/s.

7 0

3 years ago