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3 years ago

A child dangles a 1.50-kilogram stuffed toy 0.500 meters from the ground. What is the potential energy of the toy?

2 answers:

6 0

Since we know that
Gravitational potential energy = mass × height ×gravity

then

GPE = 1.5 kg x 0.500 m x 9.8m/s^2

therefore

GPE = 7.35 J

levacccp [35]3 years ago

5 0

Answer: 7.35 Joules

Explanation:

i got it right in my exam

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A wave has a wavelength of 10 mm and a frequency of 4 hertz to what is it’s speed ?

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3 years ago

Explain why astronomers use the term "blueshifted" for objects moving toward us and "redshifted" for objects moving away from us

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3 years ago

A force F with arrow applied to an object of mass m1 produces an acceleration of 3.10 m/s2. The same force applied to a second o

Bas_tet [7]

Answer:

(a) The value of the ratio m₁/m₂ is 0.581

(b) the acceleration of the combined masses is 1.139 m/s²

Explanation:

Given;

The acceleration of force applied to M₁, a₁ = 3.10 m/s²

The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²

Let this force = F

According Newton's second law of motion;

F = ma

(a) the value of the ratio m₁/m₂

since the applied force is same in both cases, M₁a₁ = M₂a₂

$\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581$

(b) the acceleration of m₁ and m₂ combined as one object under the action force F

F = ma

$a = \frac{F}{M} \\\\a = \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}$

$But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} = \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2$

Therefore, the acceleration of the combined masses is 1.139 m/s²

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3 years ago