Acceleration = force / mass = 500/45 = 11.1 m/s^2
The impulse exerted by a force F on an object in a time
is given by
In our problem, we have a force of 120 N: F=120 N, applied to the baseball for a time of
. Therefore the impulse is
East component: 3.9 m/s
South component: 1.8 m/s
Explanation:
We have to resolve the velocity vector along the east and south axis.
Taking east as positive x-direction and south as positive y-direction, the components of the velocity are given by:
where
v = 4.3 m/s is the magnitude of the velocity
is the angle between the direction of the velocity and of the x-axis
Substituting into the equations, we find:
East component:
South component:
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Answer:
The inductance of solenoid A is twice that of solenoid B
Explanation:
The inductance of a solenoid L is given by
L = μ₀n²Al where n = turns density, A = cross-sectional area of solenoid and l = length of solenoid.
Given that d₁ = 2d₂ and l₂ = 2l₁ and d₁ and d₂ are diameters of solenoids A and B respectively. Also, l₁ and l₂ are lengths of solenoids A and B respectively.
Since we have a cylindrical solenoid, the cross-section is a circle. So, A = πd²/4.
Let L₁ and L₂ be the inductances of solenoids A and B respectively.
So L₁ = μ₀n²A₁l₁ = μ₀n²πd₁²l₁/4
L₂ = μ₀n²A₂l₂ = μ₀n²πd₂²l₂/4
Since d₁ = 2d₂ and l₂ = 2l₁, sub
L₁/L₂ = μ₀n²πd₁²l₁/4 ÷ μ₀n²πd₂²l₂/4 = d₁²/d₂² × l₁/l₂ = (2d₂)²/d₂² × l₁/2l₁ = 4d₂²/d₂² × l₁/2l₁ = 4 × 1/2 = 2
L₁/L₂ = 2
L₁ = 2L₂
So, the inductance of solenoid A is twice that of solenoid B
Answer:
because the electricity always looking for a way to get to the ground
