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sdas [7]
3 years ago
6

HELP ME 99+ POINTS!!! Describe which renewable resources are used primarily to produce electricity and which renewable resources

are readily used as heat sources for homes. Enter your answer in the space provided.
Chemistry
2 answers:
Tomtit [17]3 years ago
7 0

Hello!

1) Solar

2) Wind power

3) Hydroelectric power

4) Biomass

5) Hydrogen and fuel cells

6) Geothermal power

I hope it helps!

NikAS [45]3 years ago
3 0
<span>renewable resources are used primarily to produce electricity include wind and hydro-electric power. they require large mechanical structures e.g. wind turbine and water dam in order to generate electric energy. Therefore they are not appropriate for home use.

</span><span>renewable resources are readily used as heat sources for homes include solar-water heating system in which water is heated by sunlight and circulated around the house. Wood burning for heat can also be considered a renewable resource as long as the wood comes from a sustainable logging cycle.</span>
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What was ernest rutherfords experiment
ohaa [14]

Answer: he shot tiny alpha particles throug a piece of gold foil.

Explanation:

6 0
3 years ago
The solubility of Z is 60 g/ 100 g water at 20 °C. How many grams of solution are produced when a saturated solution is prepared
V125BC [204]

Answer:

Saturated solution = 180 gram

Explanation:

Given:

Solubility of Z = 60 g / 100 g water

Given temperature =  20°C

Amount of water = 300 grams

Find:

Saturated solution

Computation:

Saturated solution = [Solubility of Z] × Amount of water

Saturated solution = [60 g / 100 g] × 300 grams

Saturated solution = [0.6] × 300 grams

Saturated solution = 180 gram

3 0
3 years ago
What is a catalyst?
luda_lava [24]

a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change.

 -  a person or thing that precipitates an event.

7 0
3 years ago
Read 2 more answers
A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.
irga5000 [103]

Answer:

1. pH = 1.23.

2. H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the pKa is:

pKa=-log(Ka)=-log(5.90x10^{-2})=1.23

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Which is also shown in net ionic notation.

Best regards!

4 0
3 years ago
From the following balanced equation,
ArbitrLikvidat [17]

Answer:

9.72 grams.

Explanation:

From the equation, 4 moles of NH₃ produce 6 moles of  water.

Therefore the reaction to product ratio of  NH₃ to H₂O is 4:6

and 2:3 into its simplest form.

The number of moles of NH₃ in 6.12 g is:

Number of moles=mass/ RMM

=6.12 g/17 G/mol

=0.36 moles.

Therefore the number of moles of H₂O produced is calculated as follows.

(0.36 Moles×3)2 = 0.54 moles

Mass= Number of moles × RMM

=0.54 moles×18g/mol

=9.72 grams.

6 0
3 years ago
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