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Butoxors [25]
3 years ago
7

Make the following conversion. 0.075 m = _____ cm 7.5 75 0.0075 0.00075

Chemistry
1 answer:
GaryK [48]3 years ago
8 0
In the given question we need to convert 0.075 meter into centimeter. For this purpose we need to know the relation between meter and centimeter. Then only this problem can be solved and the correct answer reached.
Now we know that
1 meter = 100 centimeter
Then
0.075 meter = [(100/1) * 0.075] centimeter
We know that any number when divided by 1 gives the same number.
So
0.075 meter = (100 * 0.075) centimeter
                    = (100 * 75/1000) centimeter
                    = (7500/1000) centimeter
                    = (75/10) centimeter
                    = 7.5 centimeter.
So from all the given options the correct answer to the question is 7.5 centimeter.  
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A voltaic cell is constructed in which the anode is a Zn|Zn2+ half cell and the cathode is a Fe2+|Fe3+ half cell. The half-cell
zmey [24]

Answer:

See below explanation

Explanation:

Checking the reduction potencials:

Zn⁺²/Zn° , E° = -0.76 V

Fe⁺²/Fe° , E° = -0.44 V

For which Fe⁺² will be the ion that will reduce, and Zn° will lose electrons

ANODE:    Zn° ⇄ Zn⁺² + 2e⁻

CATODE: Fe⁺² + 2e⁻ ⇄ Fe°

NET CELL REACTION: FeSO₄ (ac) + Zn° ⇄ Fe° + ZnSO₄ (ac)

In the external circuit, electrons will migrate from anode (Zn|Zn⁺²) to catode (Fe|Fe⁺²), and in the salt bridge; anions migrate from Fe⁺²|Fe compartment to Zn|Zn⁺² compartment

7 0
3 years ago
How many grams of oxygen gas are contained in a 15 L sample at 1.02 atm and 28°C? Please show your work.
vampirchik [111]

Answer:

0.019 g.

Explanation:

  • Firstly, we need to find the no. of moles of oxygen gas:
  • We can use the general law of ideal gas: <em>PV = nRT. </em>

where, P is the pressure of the gas in atm (P = 1.02 atm).

V is the volume of the gas in L (V = 15.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).

∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.

  • To find the mass of oxygen gas, we have:

<em>no. of moles = mass/molar mass.</em>

<em></em>

∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.

4 0
4 years ago
If you are supposed to put in 2/4 a cup sugar for a recipe, can you just put in a half cup of sugar?
natta225 [31]
I would assume so.

Given \frac{2}{4}, we can simplify the fraction to \frac{1}{2}

Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.

Hope this is the answer you are looking for.
8 0
3 years ago
Read 2 more answers
Which of following affects liquifaction of gases except
iogann1982 [59]

Answer:

pressure

Explanation:

gas convert to liquid at high pressure.

4 0
3 years ago
Using your answer from the previous question and any color changes in the video, which part of the salt visually responds to the
Drupady [299]

Answer:

This question is incomplete

Explanation:

This question is incomplete however, the answer is straight forward.

A salt is a compound formed as a result of the neutralization reaction between an acid and a base. The salt formed comprises of the metal from the base and the non-metal from the acid, as shown below

HCl + NaOH ⇒ NaCl + H₂O

Hence, we can say a salt has a metallic and non-metallic component.

Flame test experiment is generally used to detect the presence of metal ions by "releasing" several metallic colour change. Thus, the part of the salt that must have visually responded to the flame test is the metallic component.

4 0
3 years ago
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