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Butoxors [25]
3 years ago
7

Make the following conversion. 0.075 m = _____ cm 7.5 75 0.0075 0.00075

Chemistry
1 answer:
GaryK [48]3 years ago
8 0
In the given question we need to convert 0.075 meter into centimeter. For this purpose we need to know the relation between meter and centimeter. Then only this problem can be solved and the correct answer reached.
Now we know that
1 meter = 100 centimeter
Then
0.075 meter = [(100/1) * 0.075] centimeter
We know that any number when divided by 1 gives the same number.
So
0.075 meter = (100 * 0.075) centimeter
                    = (100 * 75/1000) centimeter
                    = (7500/1000) centimeter
                    = (75/10) centimeter
                    = 7.5 centimeter.
So from all the given options the correct answer to the question is 7.5 centimeter.  
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How many calories of heat are required to raise the temperature of 1.00kg of water from 10.2 degrees Celsius to 26.8 degrees Cel
Vika [28.1K]

Answer:

Explanation:

we know that specific heat is the amount of heat required to raise the  temperature of substance by one degree mathmeticaly

Q=mcΔT

ΔT=T2-T1

ΔT=26.8-10.2=16.6

C for water is 4.184

therefore

Q=1.00*4.184*16.6

Q=69.4 j

now we have to covert joule into calorie

1 calorie =4.2 j

x calorie=69.4 j/2

so 69.4 j =34.7 calorie thats why 34.7 calorie heat is required to raise the temperature of water from 10.2 to 26.8 degree celsius

6 0
3 years ago
Carbon-14 emits beta radiation and decays with a half life of 5730 years. Assume you start with 2.5x10^15 grams of Carbon-14, ho
saveliy_v [14]

The amount remaining at the end of 5 half-lives is 7.81×10¹³ g

From the question given above, the following data were obtained:

  • Half-life (t½) = 5730 years
  • Original amount (N₀) = 2.5×10¹⁵ g
  • Number of half-lives (n) = 5
  • Amount remaining (N) =?

The amount remaining can be obtained as follow:

N = 1/2ⁿ × N₀

N = 1/2⁵ × 2.5×10¹⁵

N = 1/32 × 2.5×10¹⁵

N = 0.03125 × 2.5×10¹⁵

N = 7.81×10¹³ g

Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g

Learn more about half-life: brainly.com/question/25783920

3 0
2 years ago
Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge
zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

To know more about Empirical Formula

brainly.com/question/14044066

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5 0
2 years ago
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erik [133]

Answer:

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Explanation:

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4 0
3 years ago
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Andrews [41]

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