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e-lub [12.9K]
3 years ago
9

_C4H6O3 + _H2O −−→ _C2H4O2 A) 1, 1, 2 B) 2, 1, 1 C) 2, 1, 2 D) 2, 2, 1

Chemistry
1 answer:
seraphim [82]3 years ago
8 0

Explanation:

dredge to do with me to do with me to do with me to do with me to do with me to

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Chemistry?! Help me balance this redox equation?
jekas [21]
I'll balance it for you :D 

HNO3 + P → <span>H3PO4 + NO 

break it down first (to see how many of each atom on each side) so 

H- 1       H-3
N-1        N-1
O-3       O-12
P-1        P-3

now u gotta make the numbers equal on both sides 

make the first H 3 so it's balanced with the other one by putting a 3 in front of it in the equation like this: 

</span>3HNO3 + P → H3PO4 + NO 
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that changes the WHOLE equation except the P because it's not attached (so now the N is also 3 and the O as well) 
   
</span>H- 3     H-3
N-3        N-1
O-9       O-12
P-1        P-3

so now the N is imbalanced on the product side, so do the same thing to fix it 

3HNO3 + P → H3PO4 + 3NO 

the O next to the N is now also 3 sooo 

H- 3     H-3
N-3        N-3
O-9       O-15
P-1        P-3

3HNO3 + 3P → H3PO4 + 3NO 

H- 3     H-3
N-3        N-3
O-9       O-15
P-3        P-3

3HNO3 + 3P → H3PO4 + 3NO 

i realized halfway through this that the O is still unbalanced SOMEHOW 

3 0
3 years ago
(a) The mass density of a gaseous compound was found to be 1.23 kg m^−3 at 330 K and 20 kPa. What is the molar mass of the compo
Luden [163]

Answer:

The molar mass of the compound is:- 168.82 g/mol

The molar mass of the gas is:- 16.38 g/mol

Explanation:

(a)

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRt

Given that:-

Pressure = 20 kPa = 20000 Pa

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = \frac {1}{101325} P (atm)

20000 Pa = \frac {20000}{101325} atm

Pressure = 0.1974 atm

Temperature = 330 K

d = 1.23 kg/m³ = 1.23 g/L

Molar mass = ?

Applying the equation as:

0.1974 atm × M = 1.23 g/L × 0.0821 L.atm/K.mol × 330 K

⇒M = 168.82 g/mol

<u>The molar mass of the compound is:- 168.82 g/mol</u>

(b)

Given that:

Pressure = 152 Torr

Temperature = 298 K

Volume = 250 cm³ = 0.25 L

Using ideal gas equation as:

PV=nRT

R = 62.3637\text{torr}mol^{-1}K^{-1}

Applying the equation as:

152 Torr × 0.25 L = n × 62.3637 L.torr/K.mol × 298 K

⇒n = 0.002045 moles

Given that :  

Mass of the gas = 33.5 mg = 0.0335 g

Molar mass = ?

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.002045\ moles&#10;= \frac{0.0335\ g}{Molar\ mass}

<u>The molar mass of the gas is:- 16.38 g/mol</u>

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