Answer:
The weight of 3.45 moles of carbon dioxide has been 151.8 grams.
Moles can be calculated as the mass of solute present with respect to the molecular mass of the solute.
Moles can be expressed as:
Moles = \rm \dfrac{weight}{molecular\;weight}
molecularweight
weight
The molecular weight of carbon dioxide has been 44 grams/mol.
The given moles of carbon dioxide = 3.45 moles.
3.45 mol = \rm \dfrac{weight}{44\;g/mol}
44g/mol
weight
Weight of carbon dioxide = 3.45 \times× 44 grams
Weight of carbon dioxide = 151.8 grams.
The weight of 3.45 moles of carbon dioxide has been 151.8 grams.
1. Blood carries oxygen from your lungs to all your body cells. Carbon dioxide diffuses from your body cells into your blood. Your blood carries carbon dioxide to your lungs to be exhaled.
2. blood carries waste products from your cells to your kidneys to be removed
3. blood transport nutrients and other substances to your body cells
4. Cells and molecules in blood fight infections and help heal wounds
Answer:
His phraseology and his turns of invention are too empirically pseudoscientific for the simplicity of nature.
Answer:
a substrate is surface or material on or from an organism lives, grows, or obtains its nourishment.
Explanation:
Hey I hope this helps.....
Answer:
2,375 cans
Explanation:
The strategy here is to use the information given to calculate the lethal dosage contained in the number of cans we will compute.
We know the lethal dosage is
Ld = 10.0 g caffeine
and we also know that the oncentration of caffeine is:
2.85 mg/ oz
So our problem simplifies to calculate how many oz will contain the lethal dose, and then given the ounces per can determine how many cans are required.
First convert the lethal dose in grams to mg:
Ld =( 10 g x 1000 mg ) = 10,000 mg caffeine
10,000 mg x ( 1 Oz / 2.85 mg ) = 28,500 oz
28500 oz x ( 1 can/12 oz ) = 2,375 cans
We could also have calculated it in one step using conversion factors:
Number of cans = 10000 mg x 1 oz/ 2.85 mg x 1 can / oz = 2,375 cans
