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Phoenix [80]
2 years ago
7

Balance the following equations and then write the net ionic equations. (Use the lowest possible whole number coefficients. Incl

ude states-of-matter in your answers. Use instead of to balance equations. Write weak electrolytes in their undissociated form. Omit any coefficients of 1).
A. (NH4)3PO4(aq) + Bi(NO3)3(aq) + BiPO4(s) + NH4NO3(aq).
B. AGOH(s) + H2SO4 (aq) + Ag, SO4(s) + H2O.
C. HCIO2 (aq) + Mn(OH)2(s) + Mn(C102)2 (aq) + H2O.
Chemistry
1 answer:
Fiesta28 [93]2 years ago
8 0

Answer:

Explanation:

A )  (NH₄)₃PO₄(aq) + Bi(NO₃)₃(aq) =  BiPO₄(s) + 3 NH₄NO₃(aq).

B₁³⁺ +   PO₄⁻³  =  Bi ( PO₄ )

B )  AgOH(s) + H₂SO₄ (aq)  =  AgSO₄(s) + H₂O.

Ag⁺  + OH⁻ + H⁺ +  2 SO₄⁻² (aq)  =  Ag(SO₄)₂(s) + H₂O.

C )  HCIO₂ (aq) + Mn(OH)₂(s) =   Mn(Cl0₂)₂ (aq) + H₂O.

     H⁺  + OH⁻  =  H₂O .

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2 years ago
Need help !!!!! ASAP
Ksivusya [100]
<h2>Hello!</h2>

The answer is:

We have that there were produced 0.120 moles of CO_{2}

n=0.120mol

<h2>Why?</h2>

We are asked to calculate the number of moles of the given gas, also, we  are given the volume, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.

The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:

PV=nRT

Where,

P is the pressure of the gas.

V is the volume of the gas.

n is the number of moles of the gas.

T is the absolute temperature of the gas (Kelvin).

R is the ideal gas constant (to work with pressure in mmHg), which is equal to:

R=62.363\frac{mmHg.L}{mol.K}

We must remember that the The Ideal Gas Law equation works with absolute temperatures (K), so, if we are given relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert it to Kelvin before we proceed to work with the equation.

We can convert from Celsius degrees to Kelvin using the following formula:

Temperature(K)=Temperature(C\°) + 273K

So, we are given the following information:

Pressure=760mmHg\\Volume=2.965L\\Temperature=25.5C\°=25.5+273K=298.5K

Now, isolating the number of moles, and substituting the given information, we have:

PV=nRT

n=\frac{PV}{RT}

n=\frac{PV}{RT}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}

n=\frac{760mmHg*2.965L}{62.363\frac{mmHg.L}{mol.K}*298.5K}\\\\n=\frac{2242mmHg.L}{18615.355\frac{mmHg.L}{mol.}}\\\\n=0.120mole

Hence, we have that there were produced 0.120 moles of CO_{2}

n=0.120mol

Have a nice day!

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Answer:

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Ionization energy refers to the energy needed to completely pull out an electron from the valence shell of a neutral gaseous atom.

First ionization energy is the energy involved in the removal of first valence electron.

<u><em>In the periodic table, down the group, as atomic radius of elements increases, the ionization energy decreases </em></u>

<u><em>Whereas, across a period, as atomic radius of elements decreases, the ionization energy increases.</em></u>

PART (A):

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PART (B):

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