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2 years ago

A glass dropped on the floor is more likely to break if the floor is concrete

1 answer:

4 0

False , (No) because if its a regular floor it will more likely break because of the flat surface but if it is concrete then it has more of a chance because it has edges and dents which will help prevent it from breaking.

You might be interested in

A square sheet of rubber has sides that are 20 cm long. What is the area of the square of rubber in cm squared?

Alinara [238K]

Answer:

400cm^2

Explanation:

sides are 20cm long Area for a square is a squared

since all the lides are of equal length you can just choose one side.

20squared is 400

20 x 20 = 400cm squared

Hope this helps :)

6 0

3 years ago

A hockey puck slides on the ice and eventually stops. How would Newton interpret this behavior?

azamat

That would be a the first law of newton's laws of motion because it stops from an external force

6 0

2 years ago

How does gravitational pull affect planets with the same mass but different distance from the sun?

Yakvenalex [24]

Answer:

it just pulls them at the same time

Explanation:

5 0

3 years ago

PLEASE HELP DUE BEFORE 11:30 TODAY!!!!

user100 [1]

Answer:

D is not the a vector quantities

4 0

3 years ago

Starting from rest, a 5.00-kg block slides 2.50 m down a rough 30.0 incline. The coeffi cient of kinetic friction between the bl

UkoKoshka [18]

Answer:

a) $W_g =61.25J$

b) $W_k = -46.25J$

c) $W_N = 0$

d) $W_g$ would be the same.

$W_k$ would decrease.

$W_N$ would be the same.

Explanation:

a) On an inclined plane the force of gravity is the sine component of the weight of the block.

$F_g = mg\sin(\theta) = 5(9.8)\sin(30^\circ)\\W_g = F_g x = 5(9.8)\sin(30^\circ)2.5 = 61.25J$

b) The friction force is equal to the normal force times coefficient of friction.

$F_k = -mg\cos(\theta)\mu_k = -5(9.8)cos(30^\circ)0.436 = -18.5 N\\W_k = -F_kx = -46.25J$

c) The work done by the normal force is zero, since there is no motion in the direction of the normal force.

d) The relation between the vertical height and the distance on the ramp is

$h = x\sin(\theta)$

According to this relation, the work done by the gravity wouldn't change, since the force of gravity includes a term of $x\sin(\theta)$ .

The work done by the friction force would decrease, because both the cosine term and the distance on the ramp would decline.

The work done by the normal force would still be zero.

5 0

2 years ago