For the answer to the question above, each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
Fx = 2 x 720cos(30)
Fx = 1247 N
<h2>
She will find the ball at a horizontal distance of 86.4 m from landed location</h2>
Explanation:
Consider the vertical motion of ball
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 2 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 100 m
Substituting
s = ut + 0.5 at²
100 = 2 x t + 0.5 x 9.81 xt²
4.905t² + 2t - 100 = 0
t = 4.32 s or t = -4.72 s
After 4.32 seconds the ball reaches ground.
Now we need to find horizontal distance traveled by ball in 4.32 seconds.
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 20 m/s
Acceleration, a = 0 m/s²
Time, t = 4.32 s
Substituting
s = ut + 0.5 at²
s = 20 x 4.32 + 0.5 x 0 x 4.32²
s = 86.4 m
She will find the ball at a horizontal distance of 86.4 m from landed location
Answer:
F = 3750 N
Explanation:
Given that,
Pressure, P = 150 Pa
Area, a = 25m²
We need to find the force applied. We know that, pressure is equal to the force acting per unit area. It can be given by :

So, the required force is 3750 N.
Answer:
Decreases
Explanation:
"Effort" usually refers to the applied force. An inclined plane decreases the force required while increasing the distance that the force is exerted over. So even though there's less force needed, the amount of work stays the same.
I guess the problem is asking for the induced emf in the coil.
Faraday-Neumann-Lenz states that the induced emf in a coil is given by:

where
N is the number of turns in the coil

is the variation of magnetic flux through the coil

is the time interval
The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:

At the end of the time interval, the coil is parallel to the field, so the final flux is zero:

Therefore, we can calculate now the induced emf by using the first formula: