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frutty [35]
3 years ago
6

When the metal was placed in the calorimeter, its temperature dropped to the equilibrium temperature. Calculate the change in te

mperature of each metal sample. Record these values in Table B of your Student Guide. What is the change in temperature for the aluminum wire? C What is the change in temperature for the steel wire? C What is the change in temperature for the lead pellets? C
Chemistry
2 answers:
Murljashka [212]3 years ago
6 0

Answer:

1st one= -79.6

2nd one= -80

3rd one= -81.2

Explanation:

MAVERICK [17]3 years ago
5 0

Answer:

1st one= -79.6

2nd one= -80

3rd one= -81.2

Explanation:

Good luck!

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Which sample contains a total of 3.0 x 10^23 molecules?
belka [17]
Given that 1 mole contains 6.02x10^23 molecules, 3.0x10^23 is just around half a mole. Then we check the number of moles for each choice:

A. This is approximately half a mole, since the molar mass of Br2 is 159.8 g/mol.
B. He has a molar mass around 4 g/mol, so this is 1 mole.
C. H2 has a molar mass of 2.02 g/mol, so this is 2 moles.
D. Li has a molar mass of around 6.97 g/mol, so this is around 2 moles.

Therefore the only choice that fits is A. 80 g of Br2.
3 0
3 years ago
Help asap <br><br> i have to get a good grade on this
baherus [9]
I think The answer is 34.5l
4 0
3 years ago
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Explanation:

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8 0
2 years ago
Describes how Anders Celsius devised the temperature scale that bears his name
shusha [124]
He used a tube of mercury and marked the height of the mercury when placed in an ice bath as 0 degrees celsius, when he placed the tube in a boiling, he marked the height of mercury and called that 100 degrees celsius, he marked it linearly between 0-100 degrees celsius
3 0
3 years ago
The solubility of calcium sulfate at 30°c is 0.209 g/100 ml solution. calculate its ksp.
inessss [21]
Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.
Balanced chemical reaction (dissociation):
CaSO₄(s) → Ba²⁺(aq) + SO₄²⁻(aq).
m(CaSO₄) = 0.209 g.
n(CaSO₄) = m(CaSO₄) ÷ M(CaSO₄).
n(CaSO₄) = 0.209 g ÷ 136.14 g/mol.
n(CaSO₄) = 0.00153 mol.
s(CaSO₄) = n(CaSO₄) ÷ V(CaSO₄).
s(CaSO₄) = 0.00153 mol ÷ 0.1 L = 0.0153 M.
Ksp = [Ca²⁺] · [SO₄²⁻].
[Ca²⁺] = [SO₄²⁻] = s(CaSO₄).
Ksp = (0.0153 M)² = 2.36·10⁻⁴.
8 0
3 years ago
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