Data:
C1 (initial concentration) = 7.5 g/L
P1 (initial pressure) = 404 kPa
C2 (final concentration) = ? (g/L)
P2 (final pressure) = 202 kPa
We apply the data to the formula of the solubility of gases in a liquid (Henry's Law), let us see:
Solving:
I hope this helps. =)
The mass of the blimp is 1.12 kg.
<em>Step 1</em>. Calculate the<em> volume of the blimp</em>.
<em>V</em> = 6.28 × 10⁹ mm³ × (1 m/1000 mm)³ = 6.28 m³
<em>Step 2</em>. Calculate the <em>mass of the helium</em>.
Mass = 6.28 m³ × (0.1786 kg/1 m³) = 1.12 kg
Answer: 122 moles
Procedure:
1) Convert all the units to the same unit
2) mass of a penny = 2.50 g
3) mass of the Moon = 7.35 * 10^22 kg (I had to arrage your numbers because it was wrong).
=> 7.35 * 10^22 kg * 1000 g / kg = 7.35 * 10^ 25 g.
4) find how many times the mass of a penny is contained in the mass of the Moon.
You have to divide the mass of the Moon by the mass of a penny
7.35 * 10^ 25 g / 2.50 g = 2.94 * 10^25 pennies
That means that 2.94 * 10^ 25 pennies have the mass of the Moon, which you can check by mulitiplying the mass of one penny times the number ob pennies: 2.50 g * 2.94 * 10^25 = 7.35 * 10^25.
5) Convert the number of pennies into mole unit. That is using Avogadros's number: 6.022 * 10^ 23
7.35 * 10^ 25 penny * 1 mol / (6.022 * 10^ 23 penny) = 1.22* 10^ 2 mole = 122 mol.
Answer: 122 mol
Answer:
B
Explanation:
Presumably the system is closed (nothing can escape or enter).
A: You're cooling the container so it shouldn't explode.
C: If the container is Closed, the volume cannot increase or decrease.
D: is also impossible for the closed container reason.
B: The pressure has to decrease because the molecules are moving slower which decreases their velocity. If that happens the Force goes down.
B: Answer
To determine the Keq, we need the chemical reaction in the system. In this case it would be:
CO + 2H2 = CH3OH
The Keq is the ration of the amount of the product and the reactant. We use the ICE table for this. We do as follows:
CO H2 CH3OH
I .42 .42 0
C -0.13 -2(0.13) 0.13
-----------------------------------------------
E = .29 0.16 0.13
Therefore,
Keq = [CH3OH] / [CO2] [H2]^2 = 0.13 / 0.29 (0.16^2)
Keq = 17.51
