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stellarik [79]
3 years ago
7

2. Which is an abiotic factor?

Chemistry
2 answers:
wariber [46]3 years ago
7 0
A should be your answer.

Sunlight is abiotic and not living.
The rest still contains biological life.

Have an awesome day! :)

From your friendly Helper-in-Training, collinjun0827
Anna11 [10]3 years ago
5 0
Yes I would say it is A
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Why is co2 so bad for our bodies and why do we need to remove it? In the context of protons and ions acid/base solution.
dezoksy [38]
Hopefully this is correct and I believe CO2 is bad because the cells in the body need oxygen to then release energy from food efficiently by carrying out aerobic respiration. And a waste product of aerobic respiration is Carbon Dioxide. And Carbon dioxide must be removed from our bodies or it them makes the blood dangerously acidic.


Hope this helps :)
3 0
3 years ago
Can someone help me with this please....<br>​
Anna007 [38]

a. vinegar

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6 0
3 years ago
The variable that we change or test in an experiment is called the
Anastaziya [24]

the variable that we change in an experiment is the Independent Variable. The dependent variable is the outcome and the constant is what remains the same throughout the experiment.

4 0
3 years ago
Read 2 more answers
What is the vapor pressure (in kPa) of ethanol, CH3CH2OH, over a solution which is composed of 18.00 mL of ethanol and 12.55 g o
ladessa [460]

Answer:

The vapor pressure of ethanol in the solution is 10,27 kPa

Explanation:

To obtain the vapor pressure of a solution it is necessary to use Raoult's law:

P_{solution} = X{solvent}P_{0solvent} <em>(1)</em>

The moles of ethanol are:

18,00mL×\frac{0,789g}{1mL}×\frac{1 mol}{46,07g} = 0,3083 mol Ethanol.

Moles of benzoic acid:

12,55 g×\frac{1mol}{122,12g} = 0,1028 mol benzoic acid.

Thus, mole fraction of solvent, X, is:

\frac{0,3083 mol}{0,3083mol+0,1028mol} =<em> 0,7499</em>

Replacing this value in (1):

P_{solution} = 0,7499*13,693kPa = <em>10,27 kPa</em>

<em></em>

I hope it helps!

7 0
3 years ago
Which of the following reasons correctly explains the color changes that take place when ethylenediamine (C2N2H8) is added to th
pickupchik [31]

Answer:

The water ligands surrounding the cobalt metal center are being replaced by ethylenediamine and chloride ligands which results in a different crystal field splitting. Thus, the energy associated with electron transitions between the do-orbitals will differ for the two compounds showing a color change.

Explanation:

The five d-orbitals are usually degenerate. Upon approach of a ligand, the d-orbitals split into two sets of orbitals depending in the nature of the crystal field.

The magnitude of crystal field splitting is affected by the nature of the ligand. Ligands having filled p-π orbitals such as ethylenediamine lead to greater crystal field splitting.

The change in the colour that takes place when ethylenediamine is added to the solution of cobalt(II) chloride occurs due to a different crystal field splitting pattern. Thus, the energy associated with electron transitions between the d-orbitals now differ for the two compounds showing a color change.

7 0
3 years ago
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