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NISA [10]
3 years ago
6

A string of decorative lights is 25 feet long. The first light on the string is 16 inches from the plug. The lights on the strin

g are spaced 4 inches apart. How many lights are there on the string?
Mathematics
1 answer:
joja [24]3 years ago
8 0
25 feet = 25 x 12 = 300 inches

First light is at 16 inches.
300 - 16 = 284 inches

Find the rest of the bulbs:
284 ÷ 4 = 71

Total number of lights = 71 + 1 = 72

Answer  72 lights
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Which equation represents the line that passes through (-3,5) and is parallel to the graph of y= -2/3x+5
Nostrana [21]
Parallel to the graph of y = -2/3x + 5
means that it has the same slope

Rewrite
y = -2/3x + b
plug in the given coordinates to solve for b
5 = -2/3(-3) + b
5 = 2 + b
subtract 2 from both sides
3 = b

plug that back into the equation
y = -2/3x + b
y = -2/3x + 3

The answer is <span>B. y= -2/3x+3</span>

This line is parallel to y = -2/3x + 5 and it passes the point (3, 5).

Hope this helps :)
4 0
3 years ago
Rite the first ten terms of a sequence whose first term is -10 and whose common difference is -2.
Lelechka [254]
-10, -10-2·1= -12, -10-2·2=-14, -10-2·3=-16, -10-2·4= -18, -10-2·5= -20,
 -10-2·6= -22, -10-2·7 =-24, -10-2·8=-26, -10-2·9=-28

a=-10
d=-2
xn=a+d(n-1)

the first ten terms are
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28

8 0
3 years ago
Gavin has $7,500 to invest. He is considering two investment options. Option A pays 4% simple interest. Option B pays 3.15% inte
Leviafan [203]

Solution:

Principal =P= $ 7,500

Option A→(Simple interest)

Rate of interest= R=4%

Time(T_{1})=4 years

Time(T_{2})=6 years

Amount= Principal + Interest(Simple or compound interest)

Formula for Simple interest

S.I=\frac{P\times R\times T}{100}

S.I_{1}=\frac{7500 *4*4}{100}=1200\\\\ S.I_{2}=\frac{7500 *4*6}{100}=1800

Total amount after 4 years when interest is simple= 7500 +1200= $ 8700

Total amount after 6 years  when interest is simple= 7500 +1800= $ 9300

Option B

Formula for amount(A) when interest is 3.15% compounded annually.

A=P*(1+\frac{R}{100})^t

A_{4}=7500*(1+\frac{3.15}{100})^4\\\\ A_{4}=7500*(\frac{103.15}{100})^4\\\\ A_{4}=7500*(1.0315)^4\\\\ A_{4}=7500*1.1320\\\\ A_{4}=8490.60

A_{6}=7500*(1+\frac{3.15}{100})^6\\\\ A_{6}=7500*(\frac{103.15}{100})^6\\\\ A_{6}=7500*(1.0315)^6\\\\ A_{6}=7500*1.2045\\\\ A_{6}=9033.9286

Total amount after 4 years when interest is compounded annually=$ 8491 (approx)

Total amount after 6 years  when interest is compounded annually=$ 9034(approx)

4 0
3 years ago
Read 2 more answers
the only difference between an isosoleces trapezoidand parallel trapezoid are that the non-parellel sides are congruent
ludmilkaskok [199]
Is this a true or false type of question
4 0
3 years ago
Find The Difference.<br> 1) 8.5-7.6=<br> 2)-2.5-17.8=<br> 3 -2.9-(-7.5)=<br> 4) 3.5-1.9=
Dahasolnce [82]

Answer:

1. 0.9

2. -20.4

3. 4.6

4. 1.6

8 0
3 years ago
Read 2 more answers
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