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Cerrena [4.2K]
2 years ago
6

PLEASE HELP! STAT! When aqueous solutions of cadmium chloride and sodium sulfide are mixed, a precipitate of cadmium sulfide for

ms, leaving soluble sodium chloride in
the solution. Include states in your answer.

Write the molecular equation for the reaction.


Write the ionic equation for the reaction.

write the net ionic equation for the reaction. ​

Chemistry
2 answers:
Marina86 [1]2 years ago
8 0

The equations are given down bellow in the picture.

aivan3 [116]2 years ago
6 0

Explanation:

Hi, when mixing cadmium chloride (CdCl2) and sodium sulfide (Na2S) the cadmium displaces the sodium from the salt making an insoluble salt that precipitates, named cadmium sulfide (CdS).

1) The global molecular equation for this reaction is:

    CdCl2 (aq) + Na2S (aq) → CdS (s) + 2 NaCl (aq)  

2) The ionic hemireactions are:

  Na+(aq) + Cl-(aq) → NaCl (aq)

  Cd+2(aq) + S-2(aq) → CdS (s)

3) The net ionic equation is:

  2 Na+(aq) + 2 Cl-(aq) + Cd+2(aq) + S-2(aq) → NaCl (aq) + CdS (s)

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How much time is needed to deposit 1.0 g of chromium metal from an aqueous solution of crcl3 using a current of 1.5 a?
PSYCHO15rus [73]
The metal component of the given compound, CrCl3, is chromium. The number of moles per 1 g of chromium is calculated through the equation below,

        n = (1 g Cr)(1 mol Cr/51.996 g Cr)
              n = 0.0192 mol Cr(3 electrons/1 mol Cr) 
                n = 0.0577 e-

Determine the number in charge by multiplying with Faraday's constant,

      C = (0.0577 mol Cr)((1 F/1 mol e-)(96485 C/ 1F)
             C = 5,566.87 C

Then, calculate time by dividing the charge with the current,

     t = 5566.87 C/1.5 A 
     t = 3711.25 minutes
     t = 61.84 hours

<span><em>Answer: 61.84 hours</em></span>


8 0
3 years ago
Read 2 more answers
Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39
nalin [4]

Answer:

ΔH° = -11 kj

Explanation:

Step 1: Data given

1)   Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g)    ΔH = −23 kJ

2)   3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g)   ΔH = −39 kJ

3)   Fe3O4(s) + CO(g) → 3 FeO(s) + CO2(g) ΔH = +18 kJ

Step 2: The balanced equation

FeO + CO → Fe + CO2

Step 3:  Calculate ΔH for the reaction FeO(s) + CO(g) → Fe(s) + CO2(g).

To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

<u>This equation we add to the second equation</u>

3Fe2O3(s) + CO(g) + 2Fe3O4(s) + 2CO(g) → 2Fe3O4(s) + CO2(g) + 6FeO(s) + 2CO2 (g)

3Fe2O3(s) + 3CO(g) →  3CO2(g) + 6FeO(s)

ΔH°  = 2*18 + (-39) = 36 - 39 =  -3 kJ

<u>This new equation we will divide by 3 </u>

3Fe2O3(s) + 3CO(g) →  3CO2(g) + 6FeO(s)

Fe2O3(s) + CO(g) →  CO2(g) + 2FeO(s)

ΔH°  =-3/3 = -1 kJ

<u>Now we will substract this new equation from the first equation</u>

Fe2O3(s) + 3CO(g) - Fe2O3(s) - CO(g) → 2Fe(s) + 3CO2(g) -2FeO(s) - CO2(g)

2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

<u>The next equation we will divide by 2</u>

2CO(g)  + 2FeO(s)  → 2Fe(s) + 2CO2(g)

CO(g)  + FeO(s)  → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

7 0
2 years ago
The acid-dissociation constants of HC3H5O3 and CH3NH3+ are given in the table below. Which of the following mixtures is a buffer
sergey [27]

Answer:

A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH

Explanation:

The pH of a buffer solution is calculated using following relation

pH=pKa+log(\frac{salt}{acid} )

Thus the pH of buffer solution will be near to the pKa of the acid used in making the buffer solution.

The pKa value of HC₃H₅O₃ acid is more closer to required pH = 4 than CH₃NH₃⁺ acid.

pKa = -log [Ka]

For HC₃H₅O₃

pKa = 3.1

For CH₃NH₃⁺

pKa = 10.64

pKb = 14-10.64 = 3.36 [Thus the pKb of this acid is also near to required pH value)

A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH

Half of the acid will get neutralized by the given base and thus will result in equal concentration of both the weak acid and the salt making the pH just equal to the pKa value.

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6 0
2 years ago
A student measures the pressure and volume of an empty water bottle to be 1. 4 atm and 2. 3 l
rewona [7]

The new volume of the bottle is 5.07 L.

<h3>What is Boyle's Law?</h3>

It is a gas law that states the pressure decrease with the increase in the pressure.

By the formula

\rm P_1V_1= P_1V_2

Given that, volume1 is 2.3l

Pressure1 is 4 atm.

Pressure2 to 0.65 atm.

V2 is to find?

Putting the values in the equation

\rm 1.4\times 2.3 = 0.65 \times V_2\\\\V_2 = 5.07 L

Thus, the new volume of the bottle is 5.07 L.

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