1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vitek1552 [10]
3 years ago
11

Which of the following is the most effective relaxation technique?

Physics
2 answers:
navik [9.2K]3 years ago
6 0

Answer:

A i am taking the test

Explanation:

nevsk [136]3 years ago
3 0

Answer:

A

Explanation:

It varies from person to person.

You might be interested in
The length of the student desk is measured using a
charle [14.2K]

Answer:

3 significant figures are in 1.02m

Explanation:

4 0
3 years ago
A particle is projected with velocity v0 directly up a slope which makes an angle α with the horizontal. Assume frictionless mot
Nikolay [14]

Answer:

a)T total = 2*Voy/(g*sin( α ))

b)α = 0º ,  T total≅∞ (the particle, goes away horizontally indefinitely)

α = 90º,  T total=2*Voy/g

Explanation:

  • Velocity in the Y axis:

Voy=Vo*sinα

  • Time to reach the maximal height :

Kinematics equation: Vfy=Voy-at

a=g*sinα ;  g is gravity

if Vfy=0 ⇒ t=T ; time to reach the maximal height

so:

0=Voy-g*sin( α )*T

T=Voy/(g*sin( α ))

  • Time required to return to the starting point:

After the object reaches its maximum height, the object descends to the starting point, the time it descends is the same as the time it rises.

So T total= 2T = 2*Voy/(g*sin( α ))

  • α = 0º , sinα=0

The particle goes totally horizontal, goes away indefinitely

T total= 2*Voy/(g*sin( α )) ≅∞

  • α = 90º, sinα=1

T total=2*Voy/g

6 0
3 years ago
Two planets in space gravitationally attract each other. if both the masses and distances are doubled, the force between them is
worty [1.4K]
The force btw then remain the same
3 0
3 years ago
So far in your life, you may have assumed that as you are sitting in your chair right now, you are not accelerating. However, th
tia_tia [17]

Answer:

a) a=33.73mm/s^{2}

b) mg>N

c) \%_{change}=0.343\%

d) a=24.07mm/s^{2}

Explanation:

In order to solve part a) of the problem, we can start by drawing a free body diagram of the presented situation. (see attached picture).

In this case, we know the centripetal acceleration is given by the following formula:

a_{c}=\omega ^{2}r

where:

\omega=\frac{2\pi}{T}

we know the period of rotation of the earth is about 24 hours, so:

T=24hr*\frac{3600s}{1hr}=86400s

so we can now find the angular speed:

\omega=\frac{2\pi}{86400s}

\omega=72.72x10^{-6} rad/s^{2}

So the centripetal acceleration will be:

a_{c} =(72.72x10^{-6} rad/s^{2})^{2}(6478x10^{3}m)

which yields:

a_{c}=33.73mm/s^{2}

b)

In order to answer part b, we must draw a free body diagram of us sitting on a chair. (See attached picture.)

So we can do a sum of forces in equilibrium:

\sum F=0

so we get that:

N-mg+ma_{c} = 0

and solve for the normal force:

N=mg-ma_{c}

In this case, we can clearly see that:

mg>mg-ma_{c}

therefore mg>N

This is because the centripetal acceleration is pulling us upwards, that will make the magnitude of the normal force smaller than the product of the mass times the acceleration of gravity.

c)

So let's calculate our weight and normal force:

Let's say we weight a total of 60kg, so:

mg=(60kg)(9.81m/s^{2})=588.6N

and let's calculate the normal force:

N=m(g-a_{c})

N=(60kg)(9.81m/s^{2}-33.73x10^{-3}m/s^{2})

N=586.58N

so now we can calculate the percentage change:

\%_{change} = \frac{mg-N}{mg}x100\%

so we get:

\%_{change} = \frac{588.6N-586.58N}{588.6N} x 100\%

\%_{change}=0.343\%

which is a really small change.

d) In order to find this acceleration, we need to start by calculating the radius of rotation at that point of earth. (See attached picture).

There, we can see that the radius can be found by using the cos function:

cos \theta = \frac{AS}{h}

In this case:

cos \theta = \frac{r}{R_{E}}

so we can solve for r, so we get:

r= R_{E}cos \theta

in this case we'll use the average radius of earch which is 6,371 km, so we get:

r = (6371x10^{3}m)cos (44.4^{o})

which yields:

r=4,551.91 km

and now we can calculate the acceleration at that point:

a=\omega ^{2}r

a=(72.72x10^{-6} rad/s)^{2}(4,551.91x10^{3}m

a=24.07 mm/s^{2}

5 0
2 years ago
2. State Newton's third law of motion.<br>​
Grace [21]

Answer:

Action and reaction are equal but act in opposite directions

4 0
3 years ago
Read 2 more answers
Other questions:
  • A 29 cm pencil is placed 35cm in front of a convex lens and is illuminated by a spotlight. the focal point of the lens is 28cm f
    8·1 answer
  • Explain why an aton is neutral
    11·1 answer
  • Which of these phrases would go in the overlap? Check all that apply.
    14·2 answers
  • What are some advantages of using the graphical method of vector resolution?
    12·1 answer
  • The freezing point of water is the same as its
    15·2 answers
  • What is determined by motion and the spacing of particles?
    9·1 answer
  • What do lines on a contour map indicate
    7·1 answer
  • K i Illeanalu plo,ppio<br>ng"i​
    8·2 answers
  • Help please!! will give brainly for full answers
    6·1 answer
  • don is 10 kilometers ahead of jane, and both are traveling forward. how long will it take jane to catch up with don if jane is t
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!