Actually the correct answer must be:
The limiting reactant in the reaction is the one which has
the lowest ratio of moles available
over coefficient in the balanced equation
This is because the actual mass or number of moles of the
reactant does not directly dictate if it is a limiting reactant, this must be
relative to the other reactants.
So the answer is:
e. none of the above
Answer:
0.25 M
Explanation:
The first step is to determine how many moles of glucose there are, which means first finding out the molar mass of glucose. Carbon has a molar mass of about 12, hydrogen 1, and oxygen 16, so the total molar mass of glucose is about 6(12)+12(1)+6(16)=180 grams. This means that 90 grams is half a mole. Half a mole of substance divided by two liters of solution is (1/2)/2=1/4, or a molarity of 0.25. Hope this helps!
Answer:
V₁ = 10 mL
Explanation:
Given data:
Initial volume of HCl = ?
Initial molarity = 3.0 M
Final molarity = 0.10 M
Final volume = 300.0 mL
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = Initial molarity
V₁ = Initial volume of HCl
M₂ =Final molarity
V₂ = Final volume
Now we will put the values.
3.0 M ×V₁ = 0.10 M×300.0 mL
3.0 M ×V₁ = 30 M.mL
V₁ = 30 M.mL /3.0 M
V₁ = 10 mL
Its mass will stay the same
